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zysi [14]
3 years ago
7

Describe some ways that industry and agriculture use physical properties to separate substances.

Physics
2 answers:
musickatia [10]3 years ago
3 0
This is more chemistry. But it is a process called fractional distillation, and it basically separates the long chained hydrocarbons from the short chained hydrocarbons through separation dependant on the boiling point of the crude oil.
Oliga [24]3 years ago
3 0

Some ways that industry and agriculture use physical properties to separate substances are as follows-  

a) Separation based on the difference in DENSITY – In the process of sedimentation, the heavier particle settles at the bottom while the lighter particle remains dissolved or float in the solvent. The settled heavier substance is then removed periodically. For example mud and sand impurities from water are removed through this process.

b) Separation based on the difference in SOLUBILITY – Some substances that remain un dissolved in any other substance can be easily removed through the process of filtration. For example –  Extraction of coffee from grounds

c) Separation based on the difference in Special metal Property – Iron possesses magnetism and thus it can be easily separated from nonmagnetic substances

d) Separation based on the difference in  Vapour pressure/Boiling Point – It is the concept behind the process of separation through Distillation. In distillation,  liquid with the lower boiling point boils first which is collected through condensation while the liquid with higher boiling point remain in the flask.  

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gtnhenbr [62]

Answer:

The necessary separation between  the two parallel plates is 0.104 mm

Explanation:

Given;

length of each side of the square plate, L = 6.5 cm = 0.065 m

charge on each plate, Q = 12.5 nC

potential difference across the plates, V = 34.8 V

Potential difference across parallel plates is given as;

V = \frac{Qd}{L^2 \epsilon_o} \\\\d = \frac{V L^2 \epsilon_o}{Q}

Where;

d is the separation or distance between the two parallel plates;

d = \frac{VL^2 \epsilon_o}{Q} \\\\d =  \frac{34.8*(0.065)^2 *8.854*10^{-12}}{12.5*10^{-9}} \\\\d = 0.000104 \ m\\\\d = 0.104 \ mm

Therefore, the necessary separation between  the two parallel plates is 0.104 mm

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3 years ago
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Montano1993 [528]

Answer:

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Explanation:

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3 years ago
In a tug of war, side A applies 10N force and side B applies 8N .which side will the rope move
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Your bike gets a flat tire. Its mass is 10 kg and you are able to accelerate your bike .5 m/s/s. What is the force on the bike..
STALIN [3.7K]

Answer:

50N

Explanation:

Given parameters:

Mass of the bike   = 10kg

Acceleration  = 5m/s²  

Unknown:

Force on the bike  = ?

Solution:

To solve this problem, we apply Newton's second law of motion.

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Answer:

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