I think it may be c, 1.7 v. I work with electricity a lot.
Answer:
Intercepts occur at x = 1, y = 0
x = 3, y = 0
Only (D) is correct
Answer:
u= 200 m/s
Explanation:
Given that
Mass of bullet ,m= 50 gm
Assume that mass of block ,M= 1.2 kg
Lets take speed of the bullet before collision = u m/s
The speed of the system after collision ,v= 8 m/s
There is no any external force ,that is why linear momentum of the system will be conserve.
Linear momentum ,P = mass x velocity
m u = (M+m)v
0.05 x u = (1.2 + 0.05 ) x 8
u= 200 m/s
Therefore the speed of the bullet just before the collision is 200 m/s.
Answer:
A) 4.035 × 10^(9) J
B) 9.29 × 10^(9) J
Explanation:
We are given;
Capacitance of the original capacitor; C = 1.33 F
Potential difference given to the original capacitor; V = 77.9 kV = 77.9 × 10³ V
A) The formula for Potential energy (U) for the original capacitor is given as:
U = ½CV²
Plugging in the relevant values, we have;
U = ½ × 1.33 × (77.9 × 10³)²
U = 4.035 × 10^(9) J
B) We are told that the capacitor with dielectric constant of 427, was replaced with one possessing a dielectric constant of 983.
Thus;
U = ½ × 1.33 × (983/427) × (77.9 × 10³)²
U = 9.29 × 10^(9) J
