Answer:
70.9pi rad/s
Explanation:
angle turned through = 16
angular acceleration = 22.6 rad/s2
angular speed = 10.2 rad/s
time = ?
angular acceleration = angular speed/time
time = 10.2/22.6
time = <u>0</u><u>.</u><u>4</u><u>5</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u>
<u>angular speed</u><u> </u><u>=</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>t</u><u>u</u><u>r</u><u>n</u><u>e</u><u>d</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u>/</u><u>t</u><u>i</u><u>m</u><u>e</u>
<u>angular speed</u><u> </u><u>=</u> (16 × 2pi)/0.45
= 70.9pi rad/s
Answer:
The current in the motor in this case is 13.2 A
Explanation:
Given:
Resistance
5 Ω
Emf
V
Induced emf
V
When motor run at half speed due to load increased then induced emf is also reduced to half of its value
So new induced emf in our case is given by,
V

Where


A
Therefore, the current in the motor in this case is 13.2 A
Via half-life equation we have:

Where the initial amount is 50 grams, half-life is 4 minutes, and time elapsed is 12 minutes. By plugging those values in we get:

There is 6.25 grams left of Ra-229 after 12 minutes.
The way in which the sample of participants is obtained from the experimental technique