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4 years ago

If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?

Physics

1 answer:

Lady_Fox [76]4 years ago

3 0

Answer:

V = I R

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

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Answer:

$v_f = 31.44 m/s$

Explanation:

initial height of the ball is given as

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now we know that

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$v = 2.78 m/s$

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$\frac{1}{2}mv_i^2 + mgh_1 = \frac{1}{2}mv_f^2$

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3 years ago

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4 years ago

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A satellite in earth orbit has a mass of 99 kg and is at an altitude of 2.02 106 m. (assume that u = 0 as r â â.) (a) what is th

Ierofanga [76]

(a) What is the potential energy: PE = -G * M * m/r

Where: M is the mass of the earth which is 5.98 * 10^24 kg.

m is the mass of the satellite.

r is the space from the center of the earth to the satellite

To conclude this distance add the radius of the earth to the altitude. Radius of the earth is 6.38 * 10^6 meters.

r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6

PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 = 4.71240095 * 10^9 J

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4 years ago

Ender and Shen are flying at each other during a battle in space. Ender moves with a velocity v1 of 12 m/s and Shen, with a mass

Shalnov [3]

Answer:

Ender's mass = 2.25 kg

Explanation:

using law of conservation of momentum .

since there is inelastic collision

given.

$let \ \ m_{1} = m \\m_{2} = 45 kg \\v_{1} = 12 m/s \\v_{2} = 9 m/s \\\\V_{3} =6.4 m/s\\using \ \ \\m_{1}v_{1} + m_{2}v_{2} = (m_{1} +m_{2})V\\m\times12 + 45\times9 = (m+45)\times6.4\\64m -12m = 405 -288\\52m =117\\m =\frac{117}{52}\\m =2.25kg$

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3 years ago