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trasher [3.6K]
2 years ago
5

How many mL of a 2.50 M K2SO4 solution are required to obtain 1.20 moles of K2SO4?

Chemistry
1 answer:
Charra [1.4K]2 years ago
6 0

The answer is: " 480 mL of [2.50 M K₂SO₄] solution."

____________

<u>Explanation</u>:

Given :
1.20 mol K₂SO₄   ⇒   <u>__?  mL </u>__  of 2.50 M K₂SO₄  ;
____________
<u>Note</u>: 2.50 M  K₂SO₄ = 2.50 mol/ L ;

____________

1.20 mol  =  \frac{1 L}{2.50 mol} ;

The units of "mols" cancel;  since "mol / mol = 1 ;

and we have:  " \frac{(1.20*1) L}{(2.50)} = [{\frac{1.20}{2.50}}] L = (0.480) L ;  
 
 →  {Note: we want to keep the appropriate number of "significant figures"; so we write our answer:  "0.48 L" ;  as:  "0.480 L" .

 → Now, we want to solve for the number of "mL ("milliliters").
 →Note the exact conversion:   "1000 mL = 1 L ;

So:  ("0.480 L") * (1000) = " 480 mL of solution." → which is our answer.
____________
Hope this helps!

____________

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In addition to having a blue color, what other characteristic do Neptune and Uranus share?
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Answer:

They are both planets made out of gas!

They both share methane, hydrogen and helium gases!

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What specific electrophile does benzene attack when it undergoes nitration??
Deffense [45]
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(BENZENE) (NITRIC ACID)(CATALYST)
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7 0
3 years ago
A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de
jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

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3 years ago
At the same temperature, a freshwater lake frezzes but a salt water bay does not because
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Ocean water freezes at a lower temperature than freshwater. ... Fresh water freezes at 32 degrees Fahrenheit but seawater freezes at about 28.4 degrees Fahrenheit , because of the salt in it.

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How many grams are in 32.2 L of CO2?
Naddika [18.5K]

Answer:

63.25 grams of CO₂

Explanation:

To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.

32.2 / 22.4

= 1.4375 moles of CO₂

Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).

12 + 32 = 44

Now we want to multiply the moles by the molar mass.

1.4375 • 44

= 63.25 grams of CO₂

This is your answer.

Hope this helps!

7 0
2 years ago
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