Question

How many mL of a 2.50 M K2SO4 solution are required to obtain 1.20 moles of K2SO4?

Answer 1

The answer is: " 480 mL of [2.50 M K₂SO₄] solution."

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Explanation:

Given :
1.20 mol K₂SO₄   ⇒   __?  mL __  of 2.50 M K₂SO₄  ;
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Note: 2.50 M  K₂SO₄ = 2.50 mol/ L ;

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1.20 mol  =  $\frac{1 L}{2.50 mol}$ ;

The units of "mols" cancel;  since "mol / mol = 1 ;

and we have:  " $\frac{(1.20*1) L}{(2.50)} = [{\frac{1.20}{2.50}}] L = (0.480) L ;$  
 
 →  {Note: we want to keep the appropriate number of "significant figures"; so we write our answer:  "0.48 L" ;  as:  "0.480 L" .

 → Now, we want to solve for the number of "mL ("milliliters").
 →Note the exact conversion:   "1000 mL = 1 L ;

So:  ("0.480 L") * (1000) = " 480 mL of solution." → which is our answer.
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Hope this helps!

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