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3 years ago

11

Of the following, which can be used to identify an element present in a sample?

1 answer:

Anuta_ua [19.1K]3 years ago

6 0

Answer:

idk but i tryed

Explanation:

The simplest way to use the periodic table to identify an element is by looking for the element’s name or elemental symbol. The periodic table can be used to identify an element by looking for the element’s atomic number. The atomic number of an element is the number of protons found within the atoms of that element.

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What is a naturally occurring solid, inorganic compound or element?

Oksana_A [137]

Answer is: <span>naturally occurring solid, inorganic compound or element is mineral.
Minerals usually have </span>crystalline form, that means than crystal constituents (atoms<span>, </span>molecules <span>or </span>ions<span>) are arranged in a highly ordered microscopic structure, forming a </span>crystal lattice<span> that extends in all directions.
</span><span>For example m</span>agnetite<span> is a </span><span>mineral of iron oxide.</span>

3 0

3 years ago

1.24 grams of magnesium phosphate tribasic dissolved in 1 L of lemon juice. What is the Ksp of the magnesium phosphate tribasic

vivado [14]

<u>Answer:</u> The solubility product of magnesium phosphate tribasic is $2.52\times 10^{-10}$

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of magnesium phosphate = 1.24 g

Molar mass of magnesium phosphate = 262.85 g/mol

Volume of solution = 1 L

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{1.24g}{262.85g/mol\times 1}\\\\\text{Molarity of solution}=4.72\times 10^{-3}M$

The equation for the ionization of the magnesium phosphate is given as:

$Mg_3(PO_4)_2\leftrightharpoons 3Mg^{2+}+2PO_4^{3-}$

Expression for the solubility product of $Mg_3(PO_4)_2$ will be:

$K_{sp}=[Mg^{2+}]^3[PO_4^{3-}]^2$

We are given:

$[Mg^{2+}]=(3\times 4.72\times 10^{-3})=1.416\times 10^{-2}M$

$[PO_4^{3-}]=(2\times 4.72\times 10^{-3})=9.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(1.416\times 10^{-2})^3\times (9.44\times 10^{-3})^2=2.52\times 10^{-10}$

Hence, the solubility product of magnesium phosphate tribasic is $2.52\times 10^{-10}$

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3 years ago

Which of these phenomena cause uneven heating of the Earth?

Umnica [9.8K]

The angle of incoming sunlight varies at different places.

7 0

3 years ago

Draw the Lewis structure for SiO2

lions [1.4K]

Answer:

i don't know

Explanation:

same also don't know yea

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3 years ago

Why is science boring

murzikaleks [220]

Answer:

cuz what we are shown in school often fails to foster curiosity in us.

Explanation:

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2 years ago

Read 2 more answers