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VladimirAG [237]
2 years ago
7

in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2

are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?
Physics
1 answer:
julia-pushkina [17]2 years ago
5 0

The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.

<u>Given the following data:</u>

Charge = -2.35 \times 10^{-6} C.

Distance = 0.100 m.

<u>Scientific data:</u>

Coulomb's constant = 8.988\times 10^9 \;Nm^2/C^2

<h3>How to calculate the net force.</h3>

In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = F₁₃ + F₂₃

Mathematically, the electrostatic force between two (2) charges is given by this formula:

F = k\frac{q_1q_2}{r^2}

<u>Where:</u>

  • q represent the charge.
  • r is the distance between two charges.
  • k is Coulomb's constant.

<u>Note:</u> d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.

For electrostatic force (F₁₃);

F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}

F₁₃ = 1.24 Newton.

For electrostatic force (F₂₃);

F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}

F₂₃ = 4.96 Newton.

Therefore, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = 1.24 + 4.96

F₃ = 6.2 Newton.

Read more on charges here: brainly.com/question/14372859

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