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3 years ago

15

Explain what major mistake producers made when editing the battle scenes for the movie Star Wars

1 answer:

Artyom0805 [142]3 years ago

4 0

Answer: Air

Explanation:

Roffns dn b bdd

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How much work is done by a 120N force applied to a box that moves 5m?

Vsevolod [243]

Answer:

600 Joules

Explanation:

Using the formula F*d*cosФ. Assuming the Ф is parallel to the motion. The work done is 600 Joules.

4 0

3 years ago

How does the voltage applied to the electric motor affect the coil's number of rotations and its rotational direction

sleet_krkn [62]

Higher voltage means faster rotation. Changing the voltage polarity changes the direction of the motor.

3 0

3 years ago

The property of water that contributes to its ability to stick to certain surfaces is called

Gekata [30.6K]

Answer: Adhesion

Explanation: Adhesion is the tendency of dissimilar particles or surfaces to cling to one another (cohesion refers to the tendency of similar or identical particles/surfaces to cling to one another). The forces that cause adhesion and cohesion can be divided into several types. This allows Particles in things like water to stick to surfaces

3 0

3 years ago

The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 9.0 s. At thi

sertanlavr [38]

Answer

given,

angular speed of the tub = 5 rev/s

time = 9 s

he tub slows to rest = 15.0 s

the angular acceleration

$\omega_f - \omega_i = \alpha t$

$\alpha = \dfrac{5-0}{9}$

$\alpha = 0.556 rev/s^2$

angular displacement

$\theta_1 = \omega_i \ t + \dfrac{1}{2}\alpha t^2$

$\theta_1 = \dfrac{1}{2}\times 0.556 \times 9^2$

$\theta_1 = 22.52 rev$

$\theta_1 = 23 rev$

case 2

now,

$\omega_i = 5 rev/s$

$\omega_f = 0 rev/s$

time = 15 s

the angular acceleration

$\omega_f - \omega_i = \alpha t$

$\alpha = \dfrac{0-5}{15}$

$v\alpha =-0.333 rev/s^2$

angular displacement

$\theta_2 = \omega_i \ t + \dfrac{1}{2}\alpha t^2$

$\theta_2 =5\times 15 -\dfrac{1}{2}\times 0.333 \times 15^2$

$\theta_2 = 37.875 rev$

$\theta_2 =38 rev$

total revolution in 24 s

= 23 + 38

= 62 revolution

8 0

3 years ago

A glass plate 2.25 mm thick, with an index of refraction of 1.80, is placed between a point source of light with wavelength 620

-BARSIC- [3]

Answer:

There are 2.71x10⁴ wavelengths between the source and the screen.

Explanation:

The number of wavelengths (N) can be calculated as follows:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

Where:

$d_{g}$ : is the distance in glass = 2.25 mm

$d_{a}$ : is the distance in air = 1.50 cm - 0.225 cm = 1.275 cm

$\lambda_{g}$ : is the wavelength in glass

$\lambda_{a}$ : is the wavelength in air = 620 nm

To find the wavelength in glass we need to use the following equation:

$n_{g}*\lambda_{g} = n_{a}*\lambda_{a}$

Where:

$n_{g}$ : is the refraction index of glass = 1.80

$n_{a}$ : is the refraction index of air = 1

$\lambda_{g} = \frac{\lambda_{a}}{n_{g}} = \frac{620 nm}{1.80} = 344.4 nm$

Hence, the number of wavelengths is:

$N = \frac{d_{g}}{\lambda_{g}} + \frac{d_{a}}{\lambda_{a}}$

$N = \frac{2.25 \cdot 10^{-3} m}{344.4 \cdot 10^{-9} m} + \frac{1.275 \cdot 10^{-2} m}{620 \cdot 10^{-9} m}$

$N = 2.71 \cdot 10^{4}$

Therefore, there are 2.71x10⁴ wavelengths between the source and the screen.

I hope it helps you!

5 0

3 years ago