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Crazy boy [7]
3 years ago
15

Explain what major mistake producers made when editing the battle scenes for the movie Star Wars

Physics
1 answer:
Artyom0805 [142]3 years ago
4 0

Answer: Air

Explanation:

Roffns dn b bdd

You might be interested in
Verify the following equations:3² ×3³=243
e-lub [12.9K]

The equations are 3^2\times \:3^3=243

What is the formula used to calculate the equation?

To solve the equation using the formula of x^{2} * x^{3}

Find the equation by using formula.

On comparing with 3^2\times \:3^3=243

We get,  =(3*3)(3*3*3)

         =9*27

  Hence the equation is   =243

To learn more about information's, refer:

brainly.com/question/28440534

#SPJ4

4 0
1 year ago
Sound waves are longitudinal waves that can travel through air. Would you expect sound waves to travel faster through a low-dens
Serjik [45]

Answer:

Sound waves travel faster in a low-density gas

Explanation:

First of all, let's remind that sound waves are pressure waves: they consist of oscillations of the particles in a medium, which oscillate back and forth along the direction of motion of the wave (longitudinal wave).

The speed of sound in an ideal gas is given by the equation

v=\sqrt{\gamma \frac{p}{\rho}}

where

\gamma is the adiabatic index of the gas

p is the gas pressure

\rho is the gas density

From the equation, we see that the speed of sound is inversely proportional to the square root of the density: therefore, the lower the density, the faster the sound waves.

So, sound waves will travel faster in a low-density gas.

6 0
3 years ago
a car with a mass of 1200 kilograms is moving around a circular curve at a uniform velocity of 20 m/s the centripetal force on t
jek_recluse [69]
Coupla things wrong with this question, Sam.
Let's clean those up first, and then we'll work on the answer.

-- The car is NOT moving with uniform velocity.
'Velocity' includes both speed and direction.  If either of these
changes, it's a change of velocity.
On a circular track, the car's direction is CONSTANTLY changing,
so its velocity is too. 
The thing that's uniform is its speed, not its velocity.

-- A 'neutron' is a subatomic particle found in the nucleus of most
atoms.  It's not a unit of force.  The unit of force is the 'Newton'.
_______________________

OK. A centripetal force of 6,000 newtons keeps 1,200 kg of mass
moving in a circle at 20 m/s.

The formula:

                                     Centripetal force = (mass) (speed)² / (radius)

Multiply each side
by 'radius':                (centripetal force) x (radius) = (mass) x (speed)²

Divide each side by
'centripetal force':       Radius = (mass) x (speed)² / (centripetal force)

Write in the numbers
that we know:              Radius = (1200 kg) (20 m/s)² / (6000 Newtons)

                                                 = (1200 kg) (400 m²/s²) / (6000 Newtons)

                                                 = (480,000 kg-m²/s²) / (6000 kg-m/s²)

                                                 = (480,000 / 6000) meters
                                                
                                                 =         80 meters .   
8 0
3 years ago
Read 2 more answers
How long would it take me to travel 48 milllion miles at 200000 mph?
MakcuM [25]
For this question, you must divide 48 million by two hundred thousand to get your answer. The quotient of these number is 240, which if reduced to days, is exactly ten days.
5 0
3 years ago
If a projectile is launched vertically from the Earth with a speed equal to the escape speed, how high above the earth's surface
Alecsey [184]

Answer: h = 3R

Explanation:

Using the law of conservation of energy,

Total energy at the beginning of the launch would be equal to total energy at any point.

kinetic energy + gravitational potential energy = constant

Initial energy of the projectile =\frac{1}{2}mv_e^2-\frac{GMm}{R}... (1)

where R is the radius of the Earth, M is the mass ofthe Earth, m is the mass of the projectile.

escape velocity, v_e=\sqrt{\frac{2GM}{R}}

Total energy at height h above the Earth where speed of the projectile is half the escape velocity:

\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} ...(2)

(1)=(2)

⇒\frac{1}{2}m(v_e/2)^2-G\frac{Mm}{R+h} = \frac{1}{2}mv_e^2-\frac{GMm}{R}

⇒G\frac{Mm}{R}-G\frac{Mm}{R+h}= \frac{1}{2}m \frac{3}{4}v_e^2 =\frac{1}{2}m \frac{3}{4} (\sqrt{\frac{2GM}{R}})^2

⇒\frac{GM(R+h-R)}{R(R+h)} = \frac{3}{4}(\frac{GM}{R})

⇒\frac{h}{R+h} = \frac{3}{4}

⇒h = 3R

Thus, at height equal to thrice radius of Earth, the speed of the projectile would reduce to half of escape velocity.  

4 0
3 years ago
Read 2 more answers
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