Answer:
Explanation:
Given:
Mass of the boat, m = 4040 kg
The driving force of engine, FB = 4660 N in west = + 4660 N
The force of wind, Fwi = 880 N in east = -880 N
The force of water, Fwa = 1400 N in east = -1400N
Total three forces are acting on the boat
Fnet= Fb+fwi+Fwa
Fnet= 4660 - 880 - 1400
Fnet= +2380N
Acceleration (a) = Force/mass
= 2380/4040
= 0.59m/s2
Answer:
250 m
Explanation:
The car in this problem is moving of uniform accelerated motion, so we can use the following suvat equation:

where
s is the distance covered
u is the initial velocity
t is the time
a is the acceleration
Assuming the car starts from rest,
u = 0
Also we know that
a = 5 m/s^2 (acceleration of the car)
t = 10 s
Substituting, we find the distance covered:

Answer:
All of the above!
Explanation:
All of the answers are true! I hope I helped!