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mamaluj [8]
2 years ago
15

8. Thermal Energy is?

Chemistry
1 answer:
Burka [1]2 years ago
4 0

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.

hope it really helps...!!!

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Describe the pattern of synthesis (combination) and decomposition reactions.
jonny [76]

Answer:

Explanation:

Synthesis is the combining of two elements or atoms into a compound/mixture. Decomposition is the breaking down of a compound/mixture into individual atoms or elements. In conclusion, on is the building up of a compund/mixture and one is breaking down.

6 0
3 years ago
What is the mole ratio of D to A in the generic chemical reaction? 4A + B --> C + D​
storchak [24]
<h3>Answer:</h3>

Mole ratio of D to A is 1 : 4

<h3>Explanation:</h3>

We are given the generic chemical equation;

4A + B → C + D​

We are supposed to determine the mole ratio of D to A

What is mole ratio?

  • Mole ratio is the ratio of the number of moles of reactants or products in a chemical reaction.
  • We determine the mole ratio using the coefficients of reactants or products in question.

For example;

  • In the equation, 4A + B → C + D​, the coefficient of A is 4 while the coefficient of D is 1.
  • This means, 4 moles of A reacts with 1 mole of b to produce 1 mole of C and 1 mole of D
  • Thus, mole ratio of D to A  is 1 : 4
6 0
3 years ago
Cube has a mass of 15g and the volume is 30cm what’s its density
lbvjy [14]
Density = mass divided by volume. 15/30 is 1/2 so the density is 1/2 or 0.5 g/cm
5 0
3 years ago
Chemistry is the study of all of the following EXCEPT
ValentinkaMS [17]
B - projectile motion
4 0
3 years ago
The coefficient of thermal expansion α = (1/V)(∂V/∂T)p. Using the equation of state, compute the value of α for an ideal gas. Th
andreyandreev [35.5K]

Answer:

The coefficient of thermal expansion α is  

      \alpha  =  \frac{1}{T}

The coefficient of compressibility

      \beta   =  \frac{1}{P}

Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

       \frac{ \delta P}{\delta  T}  =  \frac{n R }{V}

From  ideal equation

         nR  =  \frac{PV}{T}

So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

Explanation:

From the question we are told that

   The  coefficient of thermal expansion is \alpha  =  \frac{1}{V} *  (\frac{\delta V}{ \delta  P})  P

    The coefficient of compressibility is \beta  =  - (\frac{1}{V} ) *  (\frac{\delta V}{ \delta P} ) T

Generally the ideal gas is  mathematically represented as

        PV  =  nRT

=>      V  =  \frac{nRT}{P}  --- (1)

differentiating both side with respect to T at constant P

       \frac{\delta V}{\delta T }  =  \frac{ n R }{P}

substituting the equation above into \alpha

       \alpha  =  \frac{1}{V} *  ( \frac{ n R }{P})  P

        \alpha  = \frac{nR}{PV}

Recall from ideal gas equation  T =  \frac{PV}{nR}

So

          \alpha  =  \frac{1}{T}

Now differentiate equation (1) above with respect to  P  at constant T

          \frac{\delta  V}{ \delta P}  =  -\frac{nRT}{P^2}

substituting the above  equation into equation of \beta

        \beta  =  - (\frac{1}{V} ) *  (-\frac{nRT}{P^2} ) T

        \beta =\frac{ (\frac{n RT}{PV} )}{P}

Recall from ideal gas equation that

       \frac{PV}{nRT}  =  1

So

       \beta   =  \frac{1}{P}

Now  considering (\frac{ \delta P }{\delta  T} )V

From equation (1) we have that

       \frac{ \delta P}{\delta  T}  =  \frac{n R }{V}

From  ideal equation

         nR  =  \frac{PV}{T}

So

     \frac{\delta P}{\delta  T}  =  \frac{PV}{TV}

=>  \frac{\delta  P}{\delta  T}  =  \frac{P}{T}

=>   \frac{\delta  P}{\delta  T}  =  \frac{\alpha }{\beta}

5 0
3 years ago
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