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ahrayia [7]
4 years ago
14

Why is light energy written on the left side of the equation

Chemistry
1 answer:
Kipish [7]4 years ago
5 0
Energy from SUNLIGHT + CO2(g) + H2O(l) = C6H12O6 (glucose) + O2(g)
The above is unbalanced, but it shows that sunlight is on the left side of the equation.
Sunlight provides the energy for the reaction to take place, without it nothing would really happen. Therefore it is an INPUT into the equation, thus it is on the left side. Outputs are placed on the right side of the equation.
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18. An objective observation is one without
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If 84.1 g of NaOH and 51.0 g of Al and 25.0 g H20 react which chemical is the limiting reactant?
12345 [234]

Answer:

  • <u><em>H₂O</em></u>

Explanation:

<u>1. Chemical quation</u>

The reaction of aluminium, sodium hydroxide and water is represented by the balanced chemical equation:

  • 2Al(s) + 2NaOH(s) + 6H₂O(l) → 2Na[Al(OH)₄] (aq) + 3H₂(g) ↑

The coefficients of each reactant and product give the theoretical mole ratios.

To find the limiting reactant you compare the theoretical ratios with the ratio of the available substaces.

<u>2. Theoretical mole ratio:</u>

  • 2 mol Al : 2 mol NaOH : 6 mol H₂O

Equivalent to

  • 1 mol Al : 1 mol NaOH : 3 mol H₂O

<u>3. Actual ratio</u>

a) Convert each mass to number of moles

Formula:

  • number of moles = mass in grams / molar mass

Al:

  • molar mass = atomic mass = 26.982g/mol
  • number of moles = 51.0g / 26.982g/mol = 1.89 mol

NaOH:

  • molar mass = 39.997g/mol
  • number of moles = 84.1g / 39.997g/mol = 2.10 mol

H₂O:

  • molar mass = 18.015g/mol
  • number of moles = 25.0g / 18.015g/mol = 1.39 mol

Divide all the mole amounts by the least number:

  • Al: 1.89/1.39 = 1.36
  • NaOH: 2.10 = 1.52
  • H₂O: 1.39 = 1.00

  • 1.36 mol Al : 1.52 mol NaOH : 1.00 mol H₂O

<u>4. Comparison</u>

<u />

Theoretical ratio:

  • 1 mol Al : 1 mol NaOH : 3 mol H₂O

Actual ratio:

  • 1.36 mol Al : 1.52 mol NaOH : 1.00 mol H₂O

     Multiply by 3:

  • 4.08 mol Al : 4.56 mol NaOH : 3.00 mol H₂O

Now, yo can see that the first two are in excess with respect the third one, making that the water consumes first, before any of the other two consumes. Therefore, the limiting reactant is the water.

8 0
3 years ago
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