Answer:
Following is the program in C language :
#include <stdio.h> // header file
#define n 5 // macro
int main() main function
{
int a[n],k1; // variable and array declaration
printf("Enter the element:\n");
for(k1=0;k1<n;++k1) //iterating the loop
{
scanf("%d",&a[k1]);//Read the values by user
}
printf("Output in Reverse Order:\n");
for(k1=n-1;k1>=0;--k1)//iterating the loop
{
printf(" %d ",a[k1]); //Display the values
}
return 0;
}
Output:
Enter the element:
4
3
45
67
89
Output in Reverse Order: 89 67 45 3 4
Explanation:
Following is the description of the program
- Define a macro "n" with value 5 after the header file.
- Declared an array "a" and defined the size of that array by macro i.e "n".
- Read the value by the user by using scanf statement in the array "a"
- Finally In the last for loop display the values of array "a" by space.
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
Ang mararamdaman mo ay pananamlay at tila walang lakas. Ang mangyayari sayo ay magkakasakit ka at pag ipinagpatuloy mo parin ang hindi pag kain, baka hindi lang sakit aabotin mo kundi kamatayan.
Answer:
B. THE LARGER THE NETWORK, THE MORE JOB LEADS AVAILABLE
Explanation:
- BECAUSE THATS MY ANSWER, AND IM CORRECT WITH THAT
<h2>
STUDY WELL</h2>
def min(x,y):
smallest = x
if y < smallest:
smallest = y
return smallest
x = min(2,1)
print("The min is "+str(x))
Although I wouldn't recommend using the name min for a function because min is the name of an existing function. Best of luck.
