Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=
106.16×1000
17.12
=0.00016moles
Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO
2
=
44.01×1000
56.77
=0.0013
Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H
2
O==
18.02×1000
14.53
=0.0008
Moles ratios
\frac{0.0013}{0.0008}=1.625
0.0008
0.0013
=1.625
\frac{0.0008}{0.0008}=1
0.0008
0.0008
=1
Hence molecular fomula
The empirical formula is C 4H 5.
The molecular formula C8H10
Answer:
CH₂ ; 67.1 %
Explanation:
To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation
Assume 100 grams of the compound.
# mol C = 85.7 g / 12.01 g/mol = 7.14 mol
# mol H = 14.3 g / 1.008 g/mol = 14.19 mol
The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C
So the empirical formula is CH₂
For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄ reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.
We need to calculate the moles of NaBH₄ ( M.W = 37.83 g/mol )
1.203 g NaBH₄ / 37.83 g/mol = 0.0318 mol
Theoretical yield from balanced chemical equation:
0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆
Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol = 0.440 g
% yield = 0.295 g/ 0.440 g x 100 = 67.1 %
D. Chemical and Physical Properties
Answer:
B. K+cation
Explanation:
Not all that sure but hope it will help.
Answer:
2.288 Moles of NH₄NO₃
Explanation:
The Balance chemical equation is as follow:
(NH₄)₂CO₃ + 2 HNO₃ → 2 NH₄NO₃ + H₂O + CO₂
To solve this problem we will do following steps:
Finding moles of Ammonium Carbonate:
As we know,
Moles = Mass / M.Mass
So,
Moles = 110 g / 96.08 g/mol
Moles = 1.144 moles
Calculating moles of Ammonium Nitrate:
According to balance chemical equation;
1 mole of (NH₄)₂CO₃ produces = 2 moles of NH₄NO₃
So,
1.144 moles of (NH₄)₂CO₃ will produce = X moles of NH₄NO₃
Solving for X,
X = 2 moles × 1.144 moles ÷ 1 mole
X = 2.288 moles of NH₄NO₃
