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Maurinko [17]
3 years ago
5

(03.02 LC) Lithium has a 1+ charge, and oxygen has a 2− charge. A Lewis dot diagram should contain one lithium atom and two oxyg

en atoms to show how these atoms form an ionic bond. True False

Chemistry
2 answers:
tamaranim1 [39]3 years ago
8 0

false,

the lewis dot structure of lithium oxide will not include only one lithium atom and two oxygen atom,

it will include 2 lithium atom and one oxygen atom so that an ionic compound is formed.

lithium contains +1 positive charge and oxygen contains -2 negative charge so as to make an ionic bond, two lithium should give its 2 electrons to 1 atom of oxygen.

2[Li]⁺ [O]⁻²

san4es73 [151]3 years ago
5 0

Answer: The statement is false.

Explanation:

Atomic number of lithium is 3 and its electronic distribution is 2, 1. Therefore, lithium has only one electron to donate.

Whereas atomic number of oxygen is 8 and its electronic configuration is 2, 6.

So, oxygen needs two more electrons to complete its octet. Thus, two lithium atoms will donate each valence electron to an oxygen atom.

Hence, there will be two lithium atoms and one oxygen atom in a molecule of lithium oxide (Li_{2}O). Though there is sharing of electrons so the bond formed will be ionic bond.

Therefore, we can conclude that the statement a Lewis dot diagram should contain one lithium atom and two oxygen atoms to show how these atoms form an ionic bond is false.

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pH indicator. A dye that is an acid and that appears as different colors in its protonated and deprotonated forms can be used as
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pH = 7.8

Explanation:

The Henderson-Hasselbalch equation may be used to solve the problem:

pH = pKa + log([A⁻] / [HA])

The solution of concentration 0.001 M is a formal concentration, which means that it is the sum of the concentrations of the different forms of the acid. In order to find the concentration of the deprotonated form, the following equation is used:

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The values can then be substituted into the Henderson-Hasselbalch equation:

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The equation for the reaction between copper and nitric acid is vCu + wHNO3--->xCu(NO3)2 + yNO + zH2O Balance the equation an
lana [24]

Answer:

The coefficients of the balanced equation are:

  • v= 1
  • w= 4
  • x= 1
  • y= 2
  • z=2

Explanation:

The Law of Conservation of Matter, also called the Law of Conservation of Mass or the Lomonósov-Lavoisier Law, postulates that "mass is neither created nor destroyed, it is only transformed". This means that the reagents interact with each other and form new products with different physical and chemical properties than the reagents, but the amount of matter or mass before and after a transformation (chemical reaction) is always the same. In other words, then the mass before the chemical reaction is equal to the mass after the reaction.

Then, you must balance the following chemical equation:

v Cu + w HNO₃ → x Cu(NO₃)₂ + y NO + z H₂O

For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts

  • Left side:   1 copper, 1 hydrogen, 1 nitrogen and 3 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Generally, hydrogen and oxygen balance in the end. So you balance nitrogen first, because copper is already balanced (there is the same amount on both sides of the reaction). If w = 2, then:

  • Left side:   1 copper, 2 hydrogen, 2 nitrogen and 6 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

But you see then that the oxygen is unbalanced and you have less quantity in the reagents. Then w must be greater. Being w = 4:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 3 nitrogen and 8 oxygen.

Going back to the idea of ​​balancing nitrogen, being y = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 2 hydrogen, 4 nitrogen and 9 oxygen.

Balancing the hydrogen, being z = 2:

  • Left side:   1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.
  • Right side:  1 copper, 4 hydrogen, 4 nitrogen and 10 oxygen.

Since you have the same amount of each element on each side of the reaction, the reaction is balanced. Then, the balanced equation is:

Cu + 4 HNO₃ → Cu(NO₃)₂ +  2 NO + 2 H₂O

Finally:

  • <u><em>v= 1</em></u>
  • <u><em>w= 4</em></u>
  • <u><em>x= 1</em></u>
  • <u><em>y= 2</em></u>
  • <u><em>z=2</em></u>
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