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3 years ago

SOMEONE HELP ME WITH THIS ONE PLZ!

Mathematics

1 answer:

kolezko [41]3 years ago

3 0

To construct a circle that circumscribes to a triangle, you would have to construct a circle that where all vertices of the triangle are on the circle. To do this you would have to construct the perpendicular bisectors of each side with your compass and straight edge. Comment on this answer if you are unsure of how to construct a perpendicular bisect (it's a long fundamental process to describe, and I wouldn't want to lecture you one something you already know). Once you have done so, set your compass point on the point where all perpendicular bisectors intersect (they should intersect in ONE point, if not you will have to redo it). Set your other compass lead on one of the vertices and spin away! If you have done this correctly, you should hit all three vertices when spinning your compass. Hope this helps!

Fun fact: the point where all perpendicular bisectors intersect is called the circumcenter

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What is solution 7x+5y=-24 and 4x+y=42?

LenKa [72]

7x+5y=-24 (1)
4x+y=42 (2)

multiply equation (2) by 5 to get
20x+5y=210 (3)

then calculate (3)-(2) which gives you
13x=234 hence x=18
then substitute for x in either equation to get y=-30

6 0

3 years ago

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Which of the following ratios is used in finding the sine of an angle in a right triangle?

stira [4]

The ratio is called the Opposite leg or also known as Hypotenuse. Usually, in a right angle, the size of the one angle is 90 degrees while the other which is less than 90 degrees is called the hypotenuse. It is the opposite side of the angle measured 90 degrees

3 0

3 years ago

How to solve these two problems ？

puteri [66]

8) $\theta$ is -0.896 radians

9) length of arc is 41.91 cm

Solution:

Given that,

$tan\ \theta = \frac{-5}{4}$

$\theta$ is in quadrant 4

To find: $\theta$

From given,

$tan\ \theta = \frac{-5}{4}\\\\\theta = tan^{-1} \frac{-5}{4}\\\\\theta = tan^{-1} (-1.25)\\\\\theta = -51.34$

Thus value of $\theta$ is -51.34 degrees

Convert degrees to radians

$-51.34\ degree = -51.34 \times \frac{ \pi }{180}\ radian\\\\-51.34\ degree = -0.896\ radian$

Thus $\theta$ is -0.896 radians

From given,

radius = 15.4 cm

$\theta = \frac{13 \pi }{15}$

<em><u>The length of arc when angle in radians is:</u></em>

$arc\ length = r \times \theta\\\\arc\ length = 15.4 \times \frac{ 13 \pi }{15}\\\\arc\ length = 15.4 \times 2.721\\\\arc\ length = 41.91$

Thus length of arc is 41.91 cm

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3 years ago

Subtract 2m – 7q + 5 from 4p + 2q and add your result to 7m² - 3m + 9q – 1

max2010maxim [7]

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7 0

3 years ago

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Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me

Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

$V= \pi r^2 h$

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

$dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr$

So finding the partial derivatives we get

$dV =\pi r^2 dh + \pi 2r h dr$

$dV =\pi r^2 dh + 2\pi r h dr$

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

$dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)$

That give us

$V= 28 \pi \, cm^3$

Or in decimal value

$\boxed{dV= 87.96 \, cm^3}$

Thus the volume of metal in the can is 87.96 cubic cm.

6 0

3 years ago