By definition we have that the final speed is:
Vf² = Vo² + 2 * a * d
Where,
Vo: Final speed
a: acceleration
d: distance.
We cleared this expression the acceleration:
a = (Vf²-Vo²) / (2 * d)
Substituting the values:
a = ((0) ^ 2- (60) ^ 2) / ((2) * (123) * (1/5280))
a = -77268 mi / h ^ 2
its stopping distance on a roadway sloping downward at an angle of 17.0 ° is:
First you must make a free body diagram and see the acceleration of the car:
g = 32.2 feet / sec ^ 2
a = -77268 (mi / h ^ 2) * (5280/1) (feet / mi) * (1/3600) ^ 2 (h / s) ^ 2
a = -31.48 feet / sec ^ 2
A = a + g * sin (θ) = -31.48 + 32.2 * sin17.0
A = -22.07 feet / sec ^ 2
Clearing the braking distance:
Vf² = Vo² + 2 * a * d
d = (Vf²-Vo²) / (2 * a)
Substituting the values:
d = ((0) ^ 2- (60 * (5280/3600)) ^ 2) / (2 * (- 22.07))
d = 175.44 feet
answer:
its stopping distance on a roadway sloping downward at an angle of 17.0 ° is 175.44 feet
<u><em>It's called geothermal energy, and is present due to the incredible amount of heat present in Earth's interior from radioactive decay, friction, and residual heat from Earth's formation.</em></u>
<span>Make an Observation. Scientists are naturally curious about the world. ... Form a Question. After making an interesting observation, a scientific mind itches to find out more about it. ... Form a Hypothesis. ... Conduct an Experiment. ... <span>Analyze the Data and Draw a Conclusion.</span></span>
Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s.
<span>Answer : P = 3527 Pa
Explanation:
Given : height, h = 279 m
and density of air , Ď = 1.29 kg/m3
Change in pressure , P = h*Ď*g
We know that gravity, g = 9.8 m/s2
Therefore P = 279 * 1.29 * 9.8 = 3527 Pa</span>
