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Goshia [24]
3 years ago
6

Write SHORT examples of Gravitational potential energy and Elastic energy

Physics
2 answers:
Nikolay [14]3 years ago
6 0
Dropping a bouncy ball and stretching a rubber ban.
gulaghasi [49]3 years ago
3 0

Answer:

Examples of a gravitational potential energy are; a flying helicopter, objects thrown up  and examples of elastic energy are; an archers stretched bow,  a stretched rubber band

Explanation:

We will start by giving a short definition of the two terminologies

Gravitational potential energy is the energy an object possess as a result of its position above the surface of the earth.

E_{P} = mgh

where m = mass     g = gravitational field strength      h= height      and E_{P} =gravitational potential energy

Examples are; a flying helicopter, objects thrown up

Elastic energy: This occurs as a result of stretching, compressing or  deforming of an object impermanently.

E_{e}  =  \frac{1}{2} ke²

where k = spring constant       e=extension   and E_{e} =Elastic potential energy

           

examples of elastic energy are; an archers stretched bow,  a stretched rubber band

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Every individual part of a cell has a very important and specific purpose. If even one of these went wrong it would throw off the other parts and most likely damage the cell. They all work in a bit of unison, so it's very important nothing bad happens to one. Hope this helps you out! :)

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3 years ago
How do you calculate distance using deceleration and time?​
Effectus [21]

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U = initial velocity, t = time taken, s = distance covered. Deceleration Formula is used to calculate the deceleration of the given body in motion.

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3 years ago
You do 25 J of work to move a 4N object 5 meters. Find your efficiency and write down the formula.
daser333 [38]
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20/25= %80 
3 0
3 years ago
Newton’s first and second laws interactive reader
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5 0
3 years ago
An object is (starting at rest) begins to plummet towards the earth. Assuming it is in a vacuum, how fast is the object travelin
Eva8 [605]

Answer:

–50.96

Explanation:

The following data were obtained from the question:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =

a = (Vբ – Vᵢ) / t

With the above formula, we can determine how fast the object is traveling after 5 s as follow:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

a = (Vբ – Vᵢ) / t

– 9.8 = (Vբ – 0) / 5.2

– 9.8 = Vբ / 5.2

Cross multiply

Vբ = –9.8 × 5.2

Vբ = –50.96 m/s

Therefore, the object is traveling at

–50.96 m/s

8 0
3 years ago
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