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Goshia [24]
3 years ago
6

Write SHORT examples of Gravitational potential energy and Elastic energy

Physics
2 answers:
Nikolay [14]3 years ago
6 0
Dropping a bouncy ball and stretching a rubber ban.
gulaghasi [49]3 years ago
3 0

Answer:

Examples of a gravitational potential energy are; a flying helicopter, objects thrown up  and examples of elastic energy are; an archers stretched bow,  a stretched rubber band

Explanation:

We will start by giving a short definition of the two terminologies

Gravitational potential energy is the energy an object possess as a result of its position above the surface of the earth.

E_{P} = mgh

where m = mass     g = gravitational field strength      h= height      and E_{P} =gravitational potential energy

Examples are; a flying helicopter, objects thrown up

Elastic energy: This occurs as a result of stretching, compressing or  deforming of an object impermanently.

E_{e}  =  \frac{1}{2} ke²

where k = spring constant       e=extension   and E_{e} =Elastic potential energy

           

examples of elastic energy are; an archers stretched bow,  a stretched rubber band

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The conductor is initially electrically neutral, and then a charge q is placed at the center of the hollow space. Suppose the co
Anvisha [2.4K]

The total charge on the interior of the conductor is zero.

The total charge on the exterior of the conductor is 8q.

<h3>Total charge on the interior</h3>

Due to large number of electrons available for conduction in a conductor, most of the electrons moves to surface leaving zero net charge inside the conductor.

Thus, the total charge on the interior of the conductor is zero.

<h3>Total charge on the exterior</h3>

The total charge on the exterior of the conductor is calculated as follows;

Q = q + 7q = 8q

Thus, the total charge on the exterior of the conductor is 8q.

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7 0
2 years ago
A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
Ghella [55]

Answer

given,

L(t) = 10 - 3.5 t

mass of particle = 2 Kg

radius of the circle = 3.1 m

a) torque

    τ = \dfrac{dL}{dt}

    τ = \dfrac{d}{dt}(10 - 3.5 t)

    τ = -3.5 N.m

Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.

L decreases the angular acceleration upward. so, net torque is upward.

b) Moment of inertia of the particle

    I = m R^2

    I = 2 x 3.1²

    I = 19.22 kg.m²

    L = I ω

    ω = \dfrac{L}{I}

    ω = \dfrac{10 - 3.5 t}{19.22}

    ω = 0.520 - 0.182 t

  A = 0.52 rad/s             B = -0.182 rad/s²

5 0
3 years ago
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228 - 224 = 4

there is 4g of solute in the solution.
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2 years ago
3 hours into minutes
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Answer:

180

60 minutes in a hour

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