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2 years ago

Ca anyone help me with writing a lab report about the reaction between the pepper and the soap in water

Physics

1 answer:

7nadin3 [17]2 years ago

6 0

Answer:

Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.

Explanation:

Surface tension:

The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.

The pepper and soap experiment helps you to understand buoyancy force and surface tension.

Reaction between the pepper and soap is as following.

The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.

This happens because the liquid dish soap changes the surface tension of water.

And The pepper flakes are so light, it floats on the water surface due to surface tension.
when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
This pushes the pepper away from your soap covered finger.

This is the reaction that take places between soap and pepper experiment.

Learn more about Pepper and soap experiment here:

<u>brainly.com/question/9614070</u>

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a car moving with a speed of 10 metre per second is accelerator at the rate of 2 metre per second square find its velocity after

STatiana [176]

a = ( v(2) - v(1) ) ÷ ( t(2) - t(1) )

2 = ( v(2) - 10 ) ÷ ( 6 - 0 )

2 × 6 = v(2) - 10

v(2) = 12 + 10

v(2) = 22 m/s

7 0

3 years ago

A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t

vladimir1956 [14]

a) $\omega=\frac{-mvR}{I+MR^2}$

b) $v=\frac{-mvR^2}{I+MR^2}$

Explanation:

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

$L_1=0$

Later, after the girl throws the rock, the angular momentum will be:

$L_2=(I_M+I_g)\omega +L_r$

where:

$I$ is the moment of inertia of the merry-go-round

$I_g=MR^2$ is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

$\omega$ is the angular speed of the merry-go-round and the girl

$L_r=mvR$ is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

$L_1=L_2$

So we find:

$0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}$

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

The linear speed of a body in rotational motion is given by

$v=\omega r$

where

$\omega$ is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

$\omega=\frac{-mvR}{I+MR^2}$ is the angular speed

$r=R$ is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

$v=\omega R=\frac{-mvR^2}{I+MR^2}$

5 0

3 years ago

If you install special sound-reflecting windows that reduce the sound intensity level by 30.0 db , by what factor have you reduc

shusha [124]

Answer: The sound intensity was reduced by -14.77 dB.

Explanation:

The level of the intensity of the sound with respect to the reference value is called Sound Intensity level.

$L_I=10\log\frac{I}{I_o} dB$

I = Intensity of the sound

$I_o$ = Reference sound intensity

According to question, sound-reflecting windows that reduce the sound intensity level by 30.0 db .

Let the intensity of the sound be $I_o$ and reduced intensity be I.

$I=\frac{I_o}{30} dB$

$L_I=10\log\frac{I}{I_o} dB$

$L_I=10\log\frac{\frac{I_o}{30}}{I_o}=10\log\frac{1}{30} dB=-14.77 dB$

The sound intensity was reduced by -14.77 dB.

3 0

3 years ago

A 50 kg skater pushes off from a wall with a force of 200 N. What is the skater's acceleration?

lutik1710 [3]

Answer:

Explanation:

mass (m) = 50 kg

Force (F) = 200 N

Acceleration (a)= ?

WE know

F = m * a

200 = 50 * a

a = 200 / 50

a = 4 m/s²

Hope it will help :)

3 0

3 years ago

A badger is trying to cross the street. Its velocity vvv as a function of time ttt is given in the graph below where rightwards

Mrrafil [7]

Answer: -2.5

Explanation:

1/2(-5)= -2.5

-2.5(1)= -2.5

Got it right in Khan Academy. You’re welcome.

5 0

3 years ago