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2 years ago

Ca anyone help me with writing a lab report about the reaction between the pepper and the soap in water

Physics

1 answer:

7nadin3 [17]2 years ago

6 0

Answer:

Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.

Explanation:

Surface tension:

The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.

The pepper and soap experiment helps you to understand buoyancy force and surface tension.

Reaction between the pepper and soap is as following.

The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.

This happens because the liquid dish soap changes the surface tension of water.

And The pepper flakes are so light, it floats on the water surface due to surface tension.
when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
This pushes the pepper away from your soap covered finger.

This is the reaction that take places between soap and pepper experiment.

Learn more about Pepper and soap experiment here:

<u>brainly.com/question/9614070</u>

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How long does it take for 4 coulombs of charge to pass through a cross

Galina-37 [17]

Answer: 2 seconds

Explanation:

Given that,

Time (T) = ?

Charge (Q) = 4 coulombs

current (I) = 2 Amps

Since charge depends on the amount of current flowing through the wire in a given time, hence

Charge = Current x Time

Q = IT

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Time = 2 seconds

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3 years ago

The main purpose of an air bag is to stop a passenger during a car accident in a greater amount of time than if the air bag were

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Answer:

a) 45571 N

b) 22786 N

c) 4557 N

Explanation:

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In other words, the change in momentum, must be equal to the initial one, but with opposite sign.

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Now, just applying the original form of Newton's 2nd Law, we know that this change in momentum must be equal to the impulse needed to stop the person:

$\Delta p = F* \Delta t (2)$

So, as we know the magnitude of Δp from (1) and we have different Δt as givens, we can get the different values of F (in magnitude) required to stop the person for each one of them, as follows:

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$F_{2} = \frac{\Delta p}{\Delta t_{2}} = \frac{1595kgm/s}{0.07s} = 22786 N (4)$

$F_{3} = \frac{\Delta p}{\Delta t_{3}} = \frac{1595kgm/s}{0.35s} = 4557 N (5)$

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