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2 years ago

9

The scale of a map is 1:50000. A lake on the map is 6.16cm². find the actual area of the lake in hectares.

1 answer:

Mamont248 [21]2 years ago

6 0

Answer:

1.54 [km²].

Step-by-step explanation:

1) the given scale is for linear functions, the given area of the lake is quadratic function. According to this

2) actual area = given area *50000 *50000;

3) the given area=0.000616 [m²],

the actual area=0.000616*50000*50000=1540000 [m²] or 1.54 [km²].

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A canoe in still water travels at a rate of 12 miles per hour. The current today is traveling at a rate of 2 miles per hour. If

VARVARA [1.3K]

Answer:

It’s 60miles

Step-by-step explanation:

We assume the trip is "d" miles and that the "extra hour" refers to the additional time that a current of 2 mph would add. That is, we assume the reference time is for a current of 0 mph.

The time with no current is ...

time1 = distance/speed

time1 = d/12 . . . . hours

With a current of 2 mph in the opposite direction, the time is ...

time2 = d/(12 -2) = d/10

The second time is 1 hour longer than the first, so we have ...

time2 = 1 + time1

d/10 = 1 + d/12

6d = 60 + 5d . . . . multiply by 60

d = 60 . . . . . . . . . subtract 5d

The one-way distance is 60 miles.

7 0

2 years ago

PLZ Hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!The sum of two numbers is 19 and their difference is 7, What are the two num

yuradex [85]

Answer:

13 and 6

Step-by-step explanation:

4 0

2 years ago

Solve for x: x-3/4=x/10

Olin [163]

Answer:

fractions form- x= 5/6

decimal form- x=0.83

Step-by-step explanation:

5 0

3 years ago

Find the indicated nth partial sum of the arithmetic sequence.<br> −7, −3, 1, 5, . . ., n = 30

TiliK225 [7]

Step-by-step explanation:

Given the Arithmetic sequence

$-7, -3, 1, 5, . . .$

An arithmetic sequence has a constant difference d and is defined by

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-3-\left(-7\right)=4,\:\quad \:1-\left(-3\right)=4$

$\mathrm{The\:difference\:between\:all\:of\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$d=4$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=-7$

as

$a_n=a_1+\left(n-1\right)d$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=4\left(n-1\right)-7$ ∵ $d=4$

$\mathrm{Arithmetic\:sequence\:sum\:formula:}$

$n\left(a_1+\frac{d\left(n-1\right)}{2}\right)$

$\mathrm{Plug\:in\:the\:values:}$

$n=30,\:\space a_1=-7,\:\spaced=4$

$=30\left(-7+\frac{4\left(30-1\right)}{2}\right)$

$=30\left(58-7\right)$ ∵ $\frac{4\left(30-1\right)}{2}=58$

$=30\cdot \:51$

$=1530$ ∵ $\mathrm{Multiply\:the\:numbers:}\:30\cdot \:51=1530$

Therefore, the indicated nth partial sum of the arithmetic sequence is 1530.

ANOTHER METHOD

as

$a_n=4\left(n-1\right)-7$

n = 30

$\sum _{n=1}^{30}\:4\left(n-1\right)-7$

$=\sum _{n=1}^{30}4n-11$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \sum a_n+b_n=\sum a_n+\sum b_n$

$=\sum _{n=1}^{30}4n-\sum _{n=1}^{30}11$

as

$\sum _{n=1}^{30}4n=1860$

and

$\sum _{n=1}^{30}11=330$

so

$=1860-330$

$=1530$

7 0

3 years ago

a student is chosen at random from a 7th grade math class of 16 girls and 8 boys. find each probability

zavuch27 [327]

There is a total of 24 students in the class.

The probability of choosing a girl is 16/24. Which reduces down to 2/3 or 66%.

The probability of choosing a boy is 8/24. Which reduces to 1/3 or 33%.

So the student has a 66% chance of choosing a girl and 33% chance for a boy.

4 0

3 years ago