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pentagon [3]
2 years ago
11

The chemical reaction in which ammonium sulfate and

Chemistry
1 answer:
Ganezh [65]2 years ago
5 0

Answer:

Answer and Explanation: In this reaction ammonium sulfate reacts with potassium hydroxide to give aqueous potassium sulfate, gaseous ammonia, and liquid water as the products. This is essentially an acid-base reaction where the ammonium ion is donating a hydrogen ion to the hydroxide ion from the potassium hydroxide.

Explanation:

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nignag [31]

ADSORPTION: The adhesion of a liquid or gas on the surface of a solid material, forming a thin film on the surface. Not to be confused with the process of absorption.

ABSORPTION: The act or process of absorbing or of being absorbed as

4 0
3 years ago
I need HELP! What is a variable that meteorologist track to make weather forecast? The answers are either: air pressure or barom
larisa [96]
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3 0
3 years ago
Read 2 more answers
How many atoms are in 1.0 formula units of magnesium acetate?
Ray Of Light [21]

Answer:

15

Explanation:

Magnesium Acetate Mg(C2H3O2)2

Number of atoms:

Carbon = 4

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Oxygen = 4

Total = 15

7 0
3 years ago
An electron has an uncertainty in its position of 471 pm .
olya-2409 [2.1K]

<u>Answer:</u>

$\Delta x . \Delta p \geq \frac{h}{4 \pi}$

∆x is the Uncertainty in the position of the particle

∆p is the Uncertainty in the momentum of the particle

$\Delta p=\frac{h}{4 \pi \times m \times \Delta x}$

$=\frac{6.626 \times 10^{-34} \mathrm{kgm}^{2} s^{-1}}{4 \times 3.14 \times 9.109 \times 10^{-31} \mathrm{kg} \times 471 \times 10^{-12} \mathrm{m}}$

$=\frac{6.626 \times 10^{-34} \mathrm{ms}^{-1}}{53887 \times 10^{-43}}$

=1.23\times10^5 ms^{-1} is the answer

3 0
3 years ago
If hydrochloric acid is obtained commercially at a concentration of 12.1M, how many milliliters of 12.1M HCl(aq) must be used to
rewona [7]

Answer:

V_1=82.6mL

Explanation:

Hello there!

In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:

M_2V_2=M_1V_1

Thus, we solve for the initial volume, V1, as shown below:

V_1=\frac{M_2V_2}{M_1}

And plug in the initial concentration and final concentration and volume to obtain:

V_1=\frac{2000mL*0.500M}{12.1M}\\\\V_1=82.6mL

Regards!

7 0
3 years ago
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