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3 years ago

6

How many atoms are in 3.6 moles of titanium?

2 answers:

kaheart [24]3 years ago

6 0

Answer:

69420

Explanation:

Ber [7]3 years ago

6 0

Answer:

We need to calculate number atoms, which can be determined as follows: We know that 1 mol contains 6.02214076×1023 number of atoms. i.e. is Avogadro's constant. Therefore the answer to the above question is that the number of atoms in 3.5 mol of Arsenic is 2.11×104 number of atoms.

Explanation:

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The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C

Kipish [7]

Answer: 72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Putting in the values we get:

$\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles$

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

According to stoichiometry:

1 mole of $C_3H_8$ requires 5 moles of oxygen

0.45 moles of $C_3H_8$ require= $\frac{5}{1}\times 0.45=2.25$ moles of oxygen

Mass of $O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g$

72 grams of $O_2(g)$ are needed to completely burn 19.7 g $C_3H_8(g)$

7 0

3 years ago

(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial

icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

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garri49 [273]

Answer:

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Arada [10]

Answer:

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Explanation:

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makkiz [27]

Answer:

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Explanation:

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