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umka2103 [35]
3 years ago
14

Determine the temperature of 2.49 moles of gas in a 1.0-L vessel at 143

Chemistry
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

Temperature = 6.91K

Explanation:

Temperature = T

Number of Moles = 2.49moles

Volume = 1.0L

Pressure = 143kPa

R = 8.31kPa*L/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume which the gas occupies

n = number of moles of the gas

R = ideal gas constant

T = temperature of the ideal gas

PV = nRT

T = PV / nR

T = (143 * 1) / (2.49 * 8.31)

T = 143 / 20.6919

T = 6.91K

The temperature of the gas is 6.91K

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Describe the reason why a reaction between two substances comes to an end.
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8 0
3 years ago
A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?
Rama09 [41]

The frequency of the radiation is equal to 7.17  \times 10^{19} Hertz.

<u>Given the following data:</u>

  • Photon energy = 4.75 \times 10^{-14} Joules

To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

E = hf

<u>Where:</u>

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Substituting the given parameters into the formula, we have;

4.75 \times 10^{-14} = 6.626 \times 10^{-34} \times F\\\\F = \frac{4.75 \times 10^{-14}}{6.626 \times 10^{-34}}

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4 0
2 years ago
Given the standard heats of reaction
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Answer:

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M(s) → M (g ) + 20.1 kJ --- ( 1 )

X₂ ( g ) → 2X (g ) + 327.3 kJ ---- ( 2 )

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( 3 ) - 2 x ( 2 ) - ( 1 )

M( s) + 2 X₂(g) - 2 X₂ ( g ) - M(s)  → M X₄ (g ) - 98.7 kJ -  2 [ 2X (g ) + 327.3 kJ ] - M (g ) - 20.1 kJ

0 = M X₄ (g ) - 4 X (g ) - M (g ) - 773.4 kJ

4 X (g ) +  M (g ) =  M X₄ (g ) - 773.4kJ

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Bond energy of one M - X bond =  773.4 / 4 =  193.4 kJ / mole

6 0
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