Determine the temperature of 2.49 moles of gas in a 1.0-L vessel at 143

Chemistry

1 answer:

bulgar [2K]3 years ago

5 0

Answer:

Temperature = 6.91K

Explanation:

Temperature = T

Number of Moles = 2.49moles

Volume = 1.0L

Pressure = 143kPa

R = 8.31kPa*L/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume which the gas occupies

n = number of moles of the gas

R = ideal gas constant

T = temperature of the ideal gas

PV = nRT

T = PV / nR

T = (143 * 1) / (2.49 * 8.31)

T = 143 / 20.6919

T = 6.91K

The temperature of the gas is 6.91K

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kotykmax [81]

Answer:

3.41 x10⁶ torr

Explanation:

To solve this problem we need to remember the equivalency:

1 torr = 133.322 Pa

Then we can proceed to convert 4.55×10⁸ Pa into torr. To do that we just need to multiply that value by a fraction number, putting the unit that we want to convert from in the denominator, and the value we want to convert to in the numerator:

4.55x10⁸ Pa * $\frac{1torr}{133.322Pa} =$ 3.41 x10⁶ torr