Answer: equation of the tangent plane is z = 1
Step-by-step explanation:
Given equation
z = e^(-x²-y²) at point (0,0,1)
now let z = f(x,y)
Δf(x,y) = [ fx, fy ]
= (-2xe^(-x²-y²)), (-2ye^(-x²-y²))
now
Δf (0,0) = [ 0, 0 ] = [ a, b ]
equation of the tangent plane therefore will be
z - z₀ = a(x-x₀) + b(y-y₀)
z - 1 = 0(x-0) + 0(y-0)
z - 1 = 0 + 0
z = 1
Therefore equation of the tangent plane is z = 1
Answer:
I bc it has an invisible 1 at the side
Answer: 10y + 1
Step-by-step explanation:
The perimeter is the total distance round the figure.
Now, in this case it is going to be
Perimeter = 3y + 5 + 6y + y - 4
= 3y + 6y + y + 5 - 4
= 10y + 1
Answer:
Step-by-step explanation:
Set up equation
Step 1: Simplify
Step 2:Multiply by conjugate
Step 3:Simplify
We can reduce this and we must make the imaginary number and real number serpate equations.
Reduce each by 2
Answer:
The answer is 0.157
Step-by-step explanation:
I hope it helps
