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olga_2 [115]
2 years ago
7

Need help with this asap please

Mathematics
1 answer:
Rainbow [258]2 years ago
5 0
Since they are similar, that means they are proportionally the same.
So KL is similar to PN
JL is similar to PM

So,
You need to find how much bigger is the second triangle from first.
It is proportionally scaled up.

KL/JL = PN/ PM

You basically put in order of triangles. Left triangle on left side of equal sign and right triangle on right side of equal sign. You put in denominator the similar sides and numerator the similar sides (the side that is similar to the side of the other triangle)

5/6 = PN / 9
Cross-multiply
PN * 6 = 5*9
6PN = 45
PN =45/6

PN =7.5
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The sum of 28 consecutive odd positive integers is a perfect cube. Determine the smallest possible set? What is the first and la
aleksandrvk [35]

Answer:

71 + 73 + ..... + 125 = 2,744 = 14^{3}.

Step-by-step explanation:

The smallest set starts at 71.  The last term is 125.

The total is 2,744, which is 14^{3}.

3 0
3 years ago
A line with a slope of 2 passes through (3,9). Which choice is an equation of this line?
Veronika [31]

Answer:

The answer to your question is number 3.

Step-by-step explanation:

Data

slope = m = 2

Point = (3, 9)

Process

1.- Write the equation of the line in the form point-slope

               y - y1 = m(x - x1)

2.- Identify the values of x1 and y1

        x1 = 3   y1 = 9

3.- Substitution

               y - 9 = 2(x - 3)

4.- Simplify

              y - 9 = 2x - 6

              y = 2x - 6 + 9

5.- Result

              y = 2x + 3       slope y-intercept form

6 0
3 years ago
You have enough inventory ($3,000,000) to last 30 days for the current orders being processed. However, a new order came in toda
g100num [7]

Answer: 1500000

Step-by-step explanation:

The half of 3,000,000 is 1500000 so 1500000

6 0
3 years ago
Please Help Quick!!!!
erastova [34]
I think the answer is 17
6 0
3 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
3 years ago
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