Answer:
F = 534.6[N]
Explanation:
We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.
where:
Ro = density of sea water = 1027 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = wáter Depth = 6.25 [m]
Now replacing:
![P=1027*9.81*6.25\\P=62967.93[Pa]](https://tex.z-dn.net/?f=P%3D1027%2A9.81%2A6.25%5C%5CP%3D62967.93%5BPa%5D)
The net force is:
![F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]](https://tex.z-dn.net/?f=F%20%3D%20P%2AA%5C%5CF%20%3D%2062967.93%2A0.00849%5C%5CF%20%3D%20534.6%5BN%5D)
Answer:
Initial speed of stone = 12.25 m/s
Explanation:
Given:
Change in distance = 0.15 m
Force applied = 28 N
Find:
Initial speed of stone
Computation:
Using conservation of energy
(1/2)fs² = (1/2)(mv²)
fs² = (mv²)
(28)(0.15)² = (0.028)(v²)
v² = (28)(0.15)²/(0.028)
v = 12.25
Initial speed of stone = 12.25 m/s
Answer:
This question is incomplete as it lacks options, the options are:
Which change would be the most effective way to improve the validity of this experiment?
A) Increase the number of goldfish in each tank.
B) Increase the daily amount of food for each tank.
C) Create another group that is fed regular fish food.
D) Increase the number of tanks in each treatment group.
The answer is C
Explanation:
According to this question, an experiment is conducted by Trey to determine which fish food causes the most goldfish activity over a period of two weeks. In this experiment, the independent variable is the FISH FOOD which are; Swift Salmon food and Fast Flounder food. Other variables such as type of gold fish, amount of fish food, amount & type of water etc.
One of the ways to improve an experiment, which is lacking in this case is to have a CONTROL GROUP. Based on the fish foods used for each group, it is obvious that all groups in this experiment are experimental. Hence, creating another group that is fed regular fish food will serve as the CONTROL GROUP in order to compare with the experimental groups. This will improve the validity of the experiment.
Answer:
1000N,4.48m/s
Explanation:
Height(h) = 1m
P. E = 1000J
P. E = mass x acceleration due to gravity x height
Acceleration due to gravity = 10m/s
P. E = mgh
Where weight = mg
P. E = weight x height
Weight = P. E / height
Weight = 1000 / 1
Weight. 1000N
b) as he leaves the ground P. E = K. E
P. E = 1/2 mv2
P. E = 1000 , mass = weight / 10
Mass =1000/10 = 100kg
P. E = 1/2 mv2
1000 = 1/2 x 100 x v2
Multiply both sides by 2
1000 x 2 = 100 x v2
V2 = 2000/ 100
V2 =20
Square root both sides
V = square root of 20
V = 4.48m/s
I hope this was helpful, Please mark as brainliest
