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MakcuM [25]
3 years ago
10

Which has is a product of photosynthesis? A. Carbon Dioxide B. Oxygen C. Hydrogen.

Physics
2 answers:
SCORPION-xisa [38]3 years ago
6 0

I think its c. Hydrogen

spayn [35]3 years ago
5 0
The above answer is wron it will be oxygen as plant produce oxygen
It inhaled co2 and gives out o
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Bill is learning to play tennis. He does pretty well hitting the ball back to his opponent but, many times he misses the ball wh
KiRa [710]

Answer: Place his feet parallel to the baseline prior to tossing the ball

5 0
2 years ago
In Florida, once you have had your learner's license for _________________ without any traffic convictions, you will receive an
bogdanovich [222]

Answer:

One year

Explanation:

In Florida, once you have had your learner's license for 1 year without any traffic convictions, you will receive an intermediate license.

The rule for Florida is that if a driver drives safely without any conviction during that year of his trial, he will receive an intermediate license. This means that he is now completely eligible and safe to drive around Florida's roads.

I hope the answer is helpful.

Thanks for asking.

3 0
3 years ago
Radio waves transmitted through space at 3.00 ✕ 108 m/s by the Voyager spacecraft have a wavelength of 0.137 m. What is their fr
fredd [130]

Answer:

Frequency, f=2.18\times 10^9\ Hz

Explanation:

We have,

Speed of radio waves is 3\times 10^8\ m/s

Wavelength of radio waves is \lambda=0.137\ m

It is required to find the frequency of the radio waves. The speed of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.137}\\\\f=2.18\times 10^9\ Hz

So, the frequency of the radio wave is 2.18\times 10^9\ Hz.

8 0
2 years ago
If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the
kodGreya [7K]

Answer:

a)

v = 4.048 *10^6 m/s

b)  

Angular frequency =  1.92 * 10^7

Explanation:

As we know

v =  \frac{qBr}{m}

q is the charge on the electron = 3.2 * 10^{-19} C

B is the magnetic field in Tesla = 0.4 T

r is the radius of the circle = 0.21 m

mass of the electrons = 6.64 * 10^{-27} Kg

a)

Substituting the given values in above equation, we get -

v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6m/s

b)  

Angular frequency =

\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7

8 0
2 years ago
According to Coulomb's law, what happens to the attraction of two oppositely charged objects as their distance of separation inc
NARA [144]

Answer:

Option B. Decreases

Explanation:

Coulomb's law states that:

F = Kq₁q₂ / r²

Where:

F => is the force of attraction between two charges

K => is the electrical constant.

q₁ and q₂ => are the two charges

r => is the distance apart.

From the formula:

F = Kq₁q₂ / r²

The force of attraction (F) is inversely proportional to the square of their separating distance (r).

This implies that as the distance between them increase, the force of attraction between the two charges will decrease and as the distance between two charges decrease, the force of attraction between them will increase.

Considering the question given above and the illustration given above, the force of attraction will decrease as their distance of separation increases.

Option B gives the right answer to the question.

7 0
3 years ago
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