All categories

3 years ago

What happens when a cold front meets a warm front?

2 answers:

8 0

These cases are rare, but what happens is something called an occluded front. There are so many things that could be talked about and results aren't typically constant, so I recommend you look up what an occluded front is. Its basically when a cold front catches up to a warm front and forces even more warm air up, causing high amounts of precipitation.

hram777 [196]3 years ago

4 0

What happens is called an occluded front.

You might be interested in

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching

agasfer [191]

Answer:

22.5°

Explanation:

<u>Short answer</u>: The trajectories will hit the same target when the projectile is launched at complementary angles. The second angle is 90° -67.5° = 22.5°.

<u>Longer answer</u>: The horizontal speed of the snowball launched at angle α with speed s is ...

vh = s·cos(α)

Then the horizontal distance at time t is ...

x = vh·t

and the time taken to get to some distance x is ...

t = x/vh = x/(s·cos(α))

The equation for the vertical motion of the projectile is ...

y = -4.9t² +s·sin(α)·t

Substituting the above expression for t, we have y in terms of x:

y = -4.9x²/(s·cos(α))² +(s·sin(α)·x)/(s·cos(α))

Factoring gives ...

y = (x/(cos(α))(-4.9x/(s²·cos(α)) +sin(α))

The height y will be zero at x=0 and at ...

0 = -4.9x/(s²·cos(α)) +sin(α)

x = s²·sin(α)·cos(α)/4.9 = (s²/9.8)sin(2α)

So, for some alternate angle β, we want ...

sin(2α) = sin(2β)

We know this will be the case for ...

2β = 180° -2α

β = 90° -α

The second snowball should be thrown at an angle of 90°-67.5° = 22.5° to make it hit the same point as the first.

3 0

3 years ago

Help with this question.....

mariarad [96]

Answer:

$g_{moon}=1.67 [m/s^{2} ]$

Explanation:

The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

$w =m*g\\$

where:

w = weight [N]

m = mass = 0.06 [kg]

g = gravity acceleration = 10 [N/kg]

Therefore:

$w=0.06*10\\w=0.6[N]$

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

$F=W\\F = k*x$

where:

k = spring constant [N/m]

x = deformed distance = 6 [cm] = 0.06 [m]

We can find the spring constant.

$k= F/x\\k=0.6/0.06\\k=10 [N/m]$

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

$F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]$

Since this force is equal to the weight, we can now determine the gravitational acceleration.

$F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]$

6 0

3 years ago

A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.540 and

Zinaida [17]

Answer:

73.13°

Explanation:

According to snell's law,

n1sinθi = n2sinθr

n1/n2 = sinθr/sinθi

Critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°

This means i=C and r = 90°

The Snell's law formula will become

n1/n2 = sinC/sin90°

n2/n1 = 1/sinC

Where n1 is the refractive index of the less dense medium = 1.473

n2 is the refractive index of the denser medium = 1.540

Substituting the values in the formula,

1.540/1.473 = 1/sinC

1.045 = 1/sinC

SinC = 1/1.045

SinC = 0.957

C = sin^-1(0.957)

C = 73.13°

4 0

4 years ago

If you cook a marshmallow a few feet above a camp fire, it will cook mostly

nasty-shy [4]

Answer:

A) radiation.

Explanation:

Hello,

In this case, heat transfer from a body with a high temperature to a body with a lower temperature may occur when the bodies are not in direct physical contact with each other or when they are separated in space and it is is called heat radiation. Solids, liquids, or gaseous substances are able to emit energy via a process of electromagnetic radiation because of vibrational and rotational movement of their molecules and atoms.

Hence, since the camp fire is not in contact with the marshmallow and it still cooks it, we can infer that the mechanism of heat transfer is A) radiation. Moreover, both conduction and convection occur when the bodies are in contact.

Regards.

6 0

3 years ago

A ball is thrown straight up with a velocity of 16 m/s; what will be its velocity 2.0s after being released?

harkovskaia [24]

The answer for the question is 8m/s

4 0

3 years ago