Question

the celsius temperature of a 3.00-L sample gas is lowered from 80.0 C to 30.0 C what will be the resulting volume of this gas

Answer 1

i cant tell how this was solved. what did you multiply

Answer 2

The solution to your problem is as follows:

V/T = V/T (volume/temp.)=(volume/temp.) Simple proportion.
* but remember to change your Cel. to Kelvin --> by adding 273 

(3.00L)(80+273) = (X)(30+273) 
X= 2.58 L


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