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fiasKO [112]
2 years ago
12

Give the name of this alcohol.

Chemistry
1 answer:
solong [7]2 years ago
3 0

Answer:

An alcohol is an organic compound with a hydroxyl (OH) functional group on an aliphatic carbon atom. Because OH is the functional group of all alcohols, we often represent alcohols by the general formula ROH, where R is an alkyl group. Alcohols are common in nature.

Explanation:

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A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1
LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\                                             =\frac{5270g}{39.948g/mol} \\                                             =131.9mol

Temperature T=(18+273)K=291K

Pressure P=2050psi

2050* 0.0680atm\\\\=139.4atm\\

Volume V=?

PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol

Mass of 40.7mol of Ar gas:

mass of Ar gas=number of moles * its atomic mass\\\\                        =40.7mol* 39.948g/mol\\\\                        =1625.8g

Answer:

The mass of Ar gas becomes 1625.8g.

8 0
3 years ago
The density of table salt is 2.16 g/cm3. Detail the conversion into units of pounds per liter, and provide the density in lb/L.
Leona [35]

Answer:

density = 4.763pounds per liter

Explanation:

1g/cm³ = 2.205pounds per liter

2.16g/cm³ = (unknown)pounds per liter

(unknown)pounds per liter = 2.205 x 2.16 = 4.763

density = 4.763pounds per liter

4 0
3 years ago
Calculate the cell potential, E, for the following reactions at 26.29 °C using the ion concentrations provided. Then, determine
yanalaym [24]

Answer:

I will work only one of the listed equations ... you follow the given example for the remaining reactions. Thank you :-)

Rxn 1: Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s)

a) E(Pt⁺²/Fe°) = - 1.668v

b) Process is Non-spontaneous if E(cell) < 0

Explanation:

Pt°(s) + Fe⁺²(aq) ⇄ Pt⁺²(aq) + Fe°(s) ⇔

Pt°(s)|Pt⁺²[0.057M]║Fe⁺²[0.006M]|Fe°(s)

As written, Pt° is shown undergoing oxidation with Fe⁺² undergoing reduction. Applying the reduction potentials to the analytical equations for E(cell) and ΔG(cell) gives E(Pt/Fe⁺²) < 0 and ΔG(Pt/Fe⁺²) > 0 which indicate a non-spontaneous process. The following supports this conclusion.

E°(Fe⁺²) = -0.44v

E°(Pt⁺²) = +1.20v

E°(Pt/Fe⁺²) =E°(Redn) - E°(Oxidn) =E°(Fe⁺²) - E°(Pt⁺²)

= -0.44v - (+1.20v) = - 1.64v

[Fe⁺²] = 0.0066M

[Pt⁺²] = 0.057M

n = electrons transferred = 2

E(nonstd) = E°(std) - (0.0592/n)logQ);

Q = [Pt⁺²]/[Fe⁺²]

= -1.64v - (0.0592/2)log[0.057M]/[0.006M]v = -1.668v

Also, if ΔG(cell) > 0 => indicates non-spontaneous process

ΔG(Pt/Fe⁺²) = - nFE = -(2)(96,500Coulombs)((-1.664v) > 0 Kj => nonspontaneous rxn. (1 Coulomb-volt = 1 Kilojoule)

7 0
3 years ago
What is the definition of chemistry
Neporo4naja [7]

Answer:

the branch of science that deals with the identification of the substances of which matter is composed; the investigation of their properties and the ways in which they interact, combine, and change; and the use of these processes to form new substances

Explanation:

5 0
3 years ago
Read 2 more answers
I need the correct answers
bogdanovich [222]

Answer:

Acids: Tastes Sour

Has a ph less than 7

Base: Bitter

Has a ph greater than 7

slippery

Acid&Base: Conducts electricity

4 0
2 years ago
Read 2 more answers
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