Answer:
0.574moles
Explanation:
Using the general gas equation;
PV = nRT
Where;
P = pressure (atm)
V = volume (Litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (Kelvin)
According to the information provided in the question;
- Volume (V) = 12400mL = 12400/1000 = 12.4L
- Pressure (P) = 890mmHg = 890/760 = 1.17atm
- Temperature (T) = 35°C = 35 + 273 = 308K
Hence, using PV = nRT
n = PV/RT
n = 1.17 × 12.4 ÷ 0.0821 × 308
n = 14.508 ÷ 25.287
n = 0.574moles
Therefore, the number of moles of argon gas in the cylinder is 0.574moles
The solubility is the guide to the maximum amount of solute that can be dissolved in a certain amount of solvent at a certain temperature to make a saturated solution. Any amount less than this would result to unsaturated, while any amount more would result to saturated.
6 g/(50 mL * 1 L/1000 mL) = 120 g/L
Since it is less than the solubility of 125 g/L, then <em>this solution is unsaturated</em>.
Answer:
B
Explanation:
Because the sharpener is attached to an electrical outlet
The new concentrations of 
and 
are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of = number of moles/volume in lit = 0. 500 M
Number of moles = molarity of × volume in lit = 0. 500 M× 0.025 L
Number of moles of = 0.0125 mole
Molarity of = number of moles/volume in lit = 0. 38 M
Number of moles = molarity of × volume in lit = 0. 38 M× 0.025 L
Number of moles of = 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of = number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of = 0.25M
Molarity of = number of moles/volume in lit = 0.95mole/0.05L
Molarity of = 19 M
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