If the attractive forces in a substance is much less than the

What can you say about density if volume increase and mass stays the same

Tems11 [23]

Density = mass
 volume

For the sake of explanation, let's pretend the mass is 2g and the volume is 1 ml

Density = 2 g = 2 g/ml
 1 ml

Now if we increase the volume, and leave the mass the same then mass is still 2g, but we can increase the volume to 2 ml

Density = 2 g = 1 g/ml
 2 ml

Therefore we can say that if volume increases and mass stays the same, then density will decrease.

3 0

3 years ago

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Consider the general reversible reaction. Lower A upper A plus lower B upper B double-headed arrow lower C upper C plus Lower d

dimulka [17.4K]

Answer: K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction.

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is represented by the symbol $K_{eq}$

The balanced chemical reaction is:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{eq}=\frac{[C]^c\times [D]^d}{[A]^a\times [B]^b}$

Thus the correct option is K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction.

3 0

3 years ago

Consider the reaction: I2(g)+Cl2(g)⇌2ICl(g) Kp= 81.9 at 25 ∘C. Calculate ΔGrxn for the reaction at 25 ∘C under each condition: -

scoray [572]

Answer:

Part 1: - 1.091 x 10⁴ J/mol.

Part 2: - 1.137 x 10⁴ J/mol.

Explanation:

Part 1: At standard conditions:

At standard conditions Kp= 81.9.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(81.9)) = - 1.091 x 10⁴ J/mol.

Part 2: PICl = 2.63 atm; PI₂ = 0.324 atm; PCl₂ = 0.217 atm.

For the reaction:

I₂(g) + Cl₂(g) ⇌ 2ICl(g).

Kp = (PICl)²/(PI₂)(PCl₂) = (2.63 atm)²/(0.324 atm)(0.217 atm) = 98.38.

∵ ΔGrxn = -RTlnKp

∴ ΔGrxn = - (8.314 J/mol.K)(298.0 K)(ln(98.38)) = - 1.137 x 10⁴ J/mol.

6 0

3 years ago

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What is 5 divided by 2.7

Strike441 [17]

5 divided by 2.7 is 0.54

3 0

3 years ago

Which is not a type of mass movement

lana66690 [7]

Answer:

options?

Explanation:

3 0

2 years ago

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