. How many unpaired electrons does an atom of phosphorous have in its (3) 3 (4) 5 its ground complete an atom 7. A possible set of quantum numbers for the last electron added to come ground state is mg A 4 0 + 2 B 3 0 +1 - C. 4 1 -1 +2 D. 3 -72 (1) A (2) B (3) C (4) D 8. A possible set of quantum numbers to describe an m. = + (2) n = 4, = 0, m = 0, m = -% (3) n = 4, { = 5, m =0 m, a 5s subshells (1) n=512 = 5, m = 0, m, = +% (4135.0 de in the 6p orbitals? 4 What is the maximum total number of electrons possible in the portal 10. A ground-state atom of manganese has unpaired electrons and is (2) 6. diamagnetic (3) 5, paramagnetic (4)3, paramagnetic (1)6 (2)4 3) w we take away two electrons from the outer shell of strontium, it would have the same elect configuration as what element? (1) krypton (2) germanium (3) argon (4) ma 12. The orbital diagram for a ground-state nitrogen atom is 1s 2s 2p 1. I 1 I I 2. Il a al 3. 1 1 1 1 4. Il II 1 (4) 4 -1) 1 (2) 2 (3) 3 NOUNCY of 3.4 x 1011 3 -1? (1m = 109
Answer:
Explanation:
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In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:
Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:
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Non-polar Solute and Polar Solvent (and vice versa)
However the molecules in the solute and solvent are only able to make dispersion forces with each other (as they aren't both polar). This only releases very little energy. Therefore overall, more energy is required than released and hence the process won't happen.
Answer:
<u><em>Arrhenius Acid:</em></u>
According to Arrhenius concept, Acids are proton donors.
Since H₂SO₄ have a proton (H⁺ ion) and it can donate it to be made a sulphate ion, So it is an Arrhenius acid.
See the following reaction =>
<u><em>H₂SO₄ + H₂O => HSO₄ + H₃O⁺</em></u>
<u><em>Arrhenius Base:</em></u>
An Arrhenius base is a a proton acceptor.
KOH accepts the proton to to made to KOH₂ and a proton acceptor.
See the following reaction =>
<u><em>KOH + H₂o => KOH₂ + OH⁻</em></u>
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Do you go to Millbrook? 23.9kPa
