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Molodets [167]
3 years ago
15

HELP NOW FIRST=BRANILYEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Which statement describes the difference between an atom of silver and an atom of gold?
A.
They have the same number of electrons.


B.
The atomic numbers are the same.


C.
Their atomic masses are different.


D.
They have exactly the same isotopes.
Chemistry
2 answers:
Oduvanchick [21]3 years ago
8 0

Answer:C

it's c easy..........

cestrela7 [59]3 years ago
3 0

Answer:

the answer is c. their atomic masses are different clearly because an atom of gold has 79 protons and the atom can be divided multiple times. An atom of silver has an atomic number of 47. 47 electrons. Clearly different. Hope it helps :)

Explanation:

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Answer:

Unequal,different,dipole moment,dipole moment,polar

Explanation:

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2 years ago
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A galvanic cell is set up with two cells containing a cadmium electrode in 0. 250 m cd(no3)2 solution and an iron electrode in 0
Lesechka [4]

The cell potential is 0.01934 V at 25°C.

<h3>What is a galvanic cell?</h3>

A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.

The main components of a galvanic cell are

Anode – Oxidation occurs at the anode

Cathode – Reduction occurs at the cathode

Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.

Half-cells – It is important as reduction and oxidation reactions are separated into compartments.

External circuit – it helps in Conducting the flow of electrons between electrodes

At cathode,

Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)

At anode,

Fe(s)+2e^-\rightarrow Fe^{2+}(aq)

Overall cell reaction

Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)

E^o_{cell} = E^o_{cathode} - E^o_{anode}

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Nernst equation is given by

E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ

At 25°C

E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ

Here, n = 2 and log Q = log \frac{0.250}{0.050} = 0.699

E_{cell}  = 0.01934 V

The cell potential is 0.01934 V at 25°C

Learn more about galvanic cell:

brainly.com/question/13918634

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In cold, we all know temperature is lower, and we know, it reduces the movement of air, so it contracts

Hope this helps!</span>
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Classify the following amine as 1º, 2º, 3º or 4°
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Answer:

Explanation:

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Such as water or oxygen,<br> All of the matter in a what<br> is the same?
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