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Lelechka [254]
4 years ago
12

When lithium nitride, Li3N(s) , is treated with water, H2O(l) , ammonia, NH3(g) , is produced. Predict the formula of the gas pr

oduced when sodium phosphide, Na3P(s) , is treated with water. formula: Na_{3}P(aq) +H_{2}O(l) -> F_{3}(g) +NaOH(aq) Na3P(aq)+H2O(l)⟶PH3(g)+NaOH(aq) Write the balanced equation for the reaction of Na3P(s) with H2O(l) . Phases are optional. balanced equation: Na_{3}P +3 H _{2}O->PH_{3} +3NaOH
Chemistry
1 answer:
Ronch [10]4 years ago
7 0

<u>Answer:</u> The gas produced when sodium phosphide reacts with water is phosphine.

<u>Explanation:</u>

When sodium phosphide reacts with water molecule, it leads to the production of flammable, poisonous gas known as phosphine along with the production of sodium hydroxide.

The chemical reaction for the reaction of sodium phosphide with water follows the equation:

Na_3P(aq.)+3H_2O(l)\rightarrow PH_3(g)+3NaOH(aq.)

By Stoichiometry of the reaction:

1 mole of sodium phosphide reacts with 3 moles of water to produce 1 mole of phosphine gas and 3 moles of sodium hydroxide.

Hence, the gas produced when sodium phosphide reacts with water is phosphine.

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Answer:

Outer electrons.

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All bonds are localized bonds formed between two atoms by the donation of electrons from each atom.

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3 years ago
What is the density of an object with 525 grams and a volume of 15cm3?
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Answer: 35 g/cm

Explanation:

Density equals mass over volume. 525 divided by 15 is 35

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3 years ago
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A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of magnesium fluoride in
mojhsa [17]

The question is incomplete, here is the complete question:

A chemist makes 600. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a stock solution of 0.00154 mol/L magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

<u>Answer:</u> The concentration of chemist's working solution is 5.90\times 10^{-4}M

<u>Explanation:</u>

To calculate the molarity of the diluted solution (chemist's working solution), we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock magnesium fluoride solution

M_2\text{ and }V_2 are the molarity and volume of chemist's magnesium fluoride solution

We are given:

M_1=0.00154M\\V_1=230mL\\M_2=?M\\V_2=600mL

Putting values in above equation, we get:

0.00154\times 230=M_2\times 600\\\\M_2=\frac{0.00154\times 230}{600}=5.90\times 10^{-4}M

Hence, the concentration of chemist's working solution is 5.90\times 10^{-4}M

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