Answer:


Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 20 m/s
Time taken (t) = 10 sec
To Find:
(i) Acceleration (a)
(ii) Distance covered (s)
Explanation:












Answer:
I believe it's A. An installment credit has an interest rate, repayment terms and fees, and fixed payment.
A would be number 2. Newton's First Law states that an object at rest, will stay at rest and an object in motion, will stay in motion, unless acted upon by an unbalanced force. B would be number 3. His Second Law states that <span>the sum of the forces acting on a body is equal to the product of the mass of the body and the acceleration produced by the forces. And, C would be number 1. His Third Law states that for every action, there is an equal and opposite reaction. Hope this helps!</span>
Answer:
Nitrogen and oxygen are by far the most common; dry air is composed of about 78% nitrogen (N2) and about 21% oxygen (O2). Argon, carbon dioxide (CO2), and many other gases are also present in much lower amounts; each makes up less than 1% of the atmosphere's mixture of gases.
Answer:
Total distance traveled = 9 m
Explanation:
Given:
Distance travel towards north = 3 meter
Distance travel towards south = 6 meter
Find:
Total distance traveled
Computation:
Total distance traveled = Sum of total distance
Total distance traveled = Distance travel towards north + Distance travel towards south
Total distance traveled = 3 m + 6 m
Total distance traveled = 9 m