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harkovskaia [24]
4 years ago
11

Find the area of a circle with a radius r of 6 feet. Round off your answer to one decimal point. Hint: the formula for the area

of a circle is A = π r2 and π should be approximated to four decimal places. 

Physics
2 answers:
mars1129 [50]4 years ago
7 0
Hope it will help you!

Law Incorporation [45]4 years ago
3 0
If you plug in pi then round, you get 113.1 ft^2 as the area. If you use 3.1415 as pi then round, you also get 113.1 ft^2 as the area. Hope this helps!
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The 1994 Winter Olympics included the aerials competition in skiing. In this event skiers speed down a ramp that slopes sharply
kykrilka [37]

Answer: Got It!

<em>Explanation:  </em>let s = speed at launch

v = 0 at top = s sin 63 - g t

so at top

t = s sin 63/g = .0909 s

h = 13.6 = s sin 63 t - 4.9 t^2

13.6 = .081s^2 - .0405 s^2

s^2 = 336

s = 18.3 m/s

0  0

4 0
3 years ago
What other factor affected the gravitational force between the two objects in this simulation?
neonofarm [45]

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases

7 0
3 years ago
A bullet starting from rest accelerates uniformly at a rate of 1,250 meters per square second. What is the bullet's speed after
Tatiana [17]

Answer:

125,000

Explanation:

8 0
3 years ago
Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al
Citrus2011 [14]

To solve this problem we will apply the concepts related to volume, as a function of length and area, as of mass and density. Later we will take the same concept of resistance and resistivity, equal to the length per unit area. Once obtained from the known constants it will be possible to obtain the area by matching the two equations:

Mass of copper wire(m) = 1.10g = 1.10*10^{-3} kg

Density (\rho)= 8.92*10^3kg/m^3

Resistively of copper (\gamma) = 1.7*10^{-8}\Omega \cdot m

Resistance (R) = 0.390\Omega

Volume is defined as,

V= lA \text{ and }\frac{m}{\rho}

lA= \frac{1.10*10^{-3}}{8.92*10^3}

lA = 1.233*10^{-7} m^3 (1)

We know that,

\frac{l}{A} = \frac{R}{\gamma}

\frac{l}{A}= \frac{0.390\Omega}{1.7*10^{-8}\Omega m}

\frac{l}{A} = 2.2941*10^7 m^{-1} (2)

Multiplying equation we have

l^2 = (1.233*10^{-7})( 2.2941*10^7)

l^2 = 2.8286m^2

l =\sqrt{2.8286m^2}

l = 1.68m

Therefore the length of the wire is 1.68m

6 0
3 years ago
Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 39.9° wit
wariber [46]

Answer:

n=2.053

Explanation:

We will use Snell's Law defined as:

n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}

Where n values are indexes of refraction and \theta values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:

1*Sin(39.9)=n_{2}*Sin(18.2)

Solving for n_{2} yields:

n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053

Remember to use degrees for trigonometric functions instead of radians!

6 0
3 years ago
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