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harkovskaia [24]
4 years ago
11

Find the area of a circle with a radius r of 6 feet. Round off your answer to one decimal point. Hint: the formula for the area

of a circle is A = π r2 and π should be approximated to four decimal places. 

Physics
2 answers:
mars1129 [50]4 years ago
7 0
Hope it will help you!

Law Incorporation [45]4 years ago
3 0
If you plug in pi then round, you get 113.1 ft^2 as the area. If you use 3.1415 as pi then round, you also get 113.1 ft^2 as the area. Hope this helps!
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One mole of an ideal gas expands isothermally from 0.01 m3 to 0.05 m3. The final pressure of gas is 1.2 atm. [15 Marks] determin
erik [133]

Answer:

Initial pressure = 6 atm. Work = 0.144 J

Explanation:

You need to know the equation P1*V1=P2*V2, where P1 is the initial pressure, V1 is the initial volume, and P2 and V2 are the final pressure and volume respectively. So you can rearrange the terms and find that (1.2*0.05)/(0.01) = initial pressure = 6 atm. The work done by the system can be obtained calculating the are under the curve, so it is 0.144J

4 0
3 years ago
Is a mountain lion a consumer producer or decomposer
sveticcg [70]
A mountain lion is a consumer , a worm is a decomposer !
Hope this helps! :)
8 0
4 years ago
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Suppose you wanted to hold up an electron against the force of gravity by the attraction of a fixed proton some distance above i
SCORPION-xisa [38]

Answer:

The value is  r =  5.077 \  m

Explanation:

From the question we are told that

   The  Coulomb constant is  k =  9.0 *10^{9} \  N\cdot  m^2  /C^2

   The  charge on the electron/proton  is  e =  1.6*10^{-19} \  C

    The  mass of proton m_{proton} =  1.67*10^{-27} \  kg

    The  mass of  electron is  m_{electron } =  9.11 *10^{-31} \ kg

Generally for the electron to be held up by the force gravity

   Then    

       Electric force on the electron  =  The  gravitational Force

i.e  

            m_{electron} *  g  = \frac{ k *  e^2  }{r^2 }

         \frac{9*10^9 *  (1.60 *10^{-19})^2  }{r^2 }  =     9.11 *10^{-31 }  *  9.81

         r =  \sqrt{25.78}

         r =  5.077  \  m

7 0
3 years ago
What is magma composed of? Which compound is most abundant?
Nat2105 [25]
Magma is a molten and semi-molten rock mixture found under the surface of the earth. and i think silica is the most abundant. hope it helps.sorry if it's uncorrect. :)
3 0
3 years ago
Read 2 more answers
A 6.50-g sample of copper metal at 25.0°C is heated by the addition of 84.0 J of energy. The final temperature of the copper is
Mekhanik [1.2K]

Answer:

Final temperature of the copper is 59 degrees Celsius

Explanation:

It is given that,

Mass of the sample of copper metal, m = 6.5 g

Initial temperature of the metal, T_i=25^{\circ}\ C=298\ K

Heat generated, Q = 84 J

The specific heat capacity of liquid water is 0.38 J/g-K

Let T_f is the final temperature of the copper. It can be calculated using the definition of specific heat of any substance. It is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{Q}{mc}+T_i

T_f=\dfrac{84}{6.5\times 0.38}+298

T_f=332\ K

or

T_f=59^{\circ}C

So, the final temperature of the copper is 59 degrees Celsius. Hence, this is the required solution.

4 0
3 years ago
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