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harkovskaia [24]
3 years ago
11

Find the area of a circle with a radius r of 6 feet. Round off your answer to one decimal point. Hint: the formula for the area

of a circle is A = π r2 and π should be approximated to four decimal places. 

Physics
2 answers:
mars1129 [50]3 years ago
7 0
Hope it will help you!

Law Incorporation [45]3 years ago
3 0
If you plug in pi then round, you get 113.1 ft^2 as the area. If you use 3.1415 as pi then round, you also get 113.1 ft^2 as the area. Hope this helps!
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A ball having a weight of 1.5 N is dropped from a height of 4 meters. (Neglect air friction.) How much mechanical energy is "los
NikAS [45]
As this mechanical energy is associated with height, it would be "Potential Energy" in particular.

U = mgh
U = F.h
U = 1.5 * 4
U = 6 Joules

So, 6 J of energy is lost before it hits the ground.

Hope this helps!
4 0
3 years ago
Read 2 more answers
A 30.0 kg object rests on a flat, frictionless surface. A rope lifts up on the object with a force of 309 N. What is the acceler
saveliy_v [14]
Total force = Frope - mg = 309-300
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9 = 30a
4 0
3 years ago
A long, straight, cylindrical wire of radius R carries a current uniformly distributed over its cross section.
Mice21 [21]

Answer:

Explanation:

We shall solve this question with the help of Ampere's circuital law.

Ampere's ,law

∫ B dl = μ₀ I , B is magnetic field at distance x from the axis within wire

we shall find magnetic field at distance x . current enclosed in the area of circle of radius x

=  I x π x²  / π R²

= I x²  /  R²

B x 2π x = μ₀  x current enclosed

B x 2π x = μ₀  x  I x²  /  R²

B =  μ₀   I x  / 2π R²

Maximum magnetic B₀ field  will be when x = R

B₀ = μ₀I   / 2π R

Given

B = B₀ / 3

μ₀   I x  / 2π R² = μ₀I   / 2π R x 3

x = R / 3

b ) The largest value of magnetic field is on the surface of wire

B₀ = μ₀I   / 2π R

At distance x outside , let magnetic field be B

Applying Ampere's circuital law

∫ B dl = μ₀ I

B x 2π x = μ₀ I

B = μ₀ I / 2π x

Given B = B₀ / 3

μ₀ I / 2π x = μ₀I   / 2π R x 3

x = 3R .

3 0
3 years ago
The amount of intensity and duration of sunlight striking earth vary with latitude
Natali5045456 [20]
Its true for sure
 
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8 0
3 years ago
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A simple pendulum consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field. Check all that
9966 [12]

Answer:

f.The period is independent of the suspended mass.

Explanation:

The period of a pendulum is given by

T=2 \pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration due to gravity

From the formula, we see that:

1) the period of the pendulum depends only on its length, L, and it is proportional to the square root of the length

2) the period does not depend neither on the mass of the pendulum, nor on its amplitude of oscillation

So, the only correct statements are

f.The period is independent of the suspended mass.

Note: statement "e.The period is proportional to the length of the wire" is also wrong, because the period is NOT proportional to the length of the wire, but it is proportional to the square root of it.

3 0
3 years ago
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