Add 273 to 25 to get Celsius. You always use that number when converting from Kelvin to Celsius
Answer:
Core samples are small portions of a formation taken from an existing well and used for geologic analysis. The sample is analyzed to determine porosity, permeability, fluid content, geologic age, and probable productivity of oil from the site. ... Core samples reveal the physical and chemical nature of the rock.
Electrical energy to thermal energy
a) See free-body diagram in attachment
b) The acceleration is 
Explanation:
a)
The free-body diagram of an object is a diagram representing all the forces acting on the object. Each force is represented by a vector of length proportional to the magnitude of the force, pointing in the same direction as the force.
The free-body diagram for this object is shown in the figure in attachment.
There are three forces acting on the object:
- The weight of the object, labelled as
(where m is the mass of the object and g is the acceleration of gravity), acting downward - The applied force,
, acting up along the plane - The force of friction,
, acting down along the plane
b)
In order to find the acceleration of the object, we need to write the equation of the forces acting along the direction parallel to the incline. We have:
where:
is the applied force, pushing forward
is the frictional force, acting backward
is the component of the weight parallel to the incline, acting backward, where
m = 2 kg is the mass of the object
is the acceleration of gravity
is the angle between the horizontal and the incline (it is not given in the problem, so I assumed this value)
a is the acceleration
Solving for a, we find:
Learn more about inclined planes:
brainly.com/question/5884009
#LearnwithBrainly
The ship floats in water due to the buoyancy Fb that is given by the equation:
Fb=ρgV, where ρ is the density of the liquid, g=9.81 m/s² is the acceleration of the force of gravity and V is volume of the displaced liquid.
The density of fresh water is ρ₁=1000 kg/m³.
The density of salt water is in average ρ₂=1025 kg/m³.
To compare the volumes of liquids that are displaced by the ship we can take the ratio of buoyancy of salt water Fb₂ and the buoyancy of fresh water Fb₁.
The gravity force of the ship Fg=mg, where m is the mass of the ship and g=9.81 m/s², is equal to the force of buoyancy Fb₁ and Fb₂ because the mass of the ship doesn't change:
Fg=Fb₁ and Fg=Fb₂. This means Fb₁=Fb₂.
Now we can write:
Fb₂/Fb₁=(ρ₂gV₂)/(ρ₁gV₁), since Fb₁=Fb₂, they cancel out:
1/1=1=(ρ₂gV₂)/(ρ₁gV₁), g also cancels out:
(ρ₂V₂)/(ρ₁V₁)=1, now we can input ρ₁=1000 kg/m³ and ρ₂=1025 kg/m³
(1025V₂)/(1000V₁)=1
1.025(V₂/V₁)=1
V₂/V₁=1/1.025=0.9756, we multiply by V₁
V₂=0.9756V₁
Volume of salt water V₂ displaced by the ship is smaller than the volume of sweet water V₁ because the force of buoyancy of salt water is greater than the force of fresh water because salt water is more dense than fresh water.
