R01= 14.1 Ω
R02= 0.03525Ω
<h3>Calculations and Parameters</h3>
Given:
K= E2/E1 = 120/2400
= 0.5
R1= 0.1 Ω, X1= 0.22Ω
R2= 0.035Ω, X2= 0.012Ω
The equivalence resistance as referred to both primary and secondary,
R01= R1 + R2
= R1 + R2/K2
= 0.1 + (0.035/9(0.05)^2)
= 14.1 Ω
R02= R2 + R1
=R2 + K^2.R1
= 0.035 + (0.05)^2 * 0.1
= 0.03525Ω
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Answer:
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Explanation:
The absolute pressure in psia being measured is; 27.228 psia
<h3>What is the absolute Pressure?</h3>
Formula for absolute Pressure is;
Absolute pressure = Atmospheric pressure + Gauge pressure
P_{abs} = P_{atm} + P_g
We are given;
P_atm = 29.86 (in Hg) = 14.666 psia
Density of mercury at 70 °F; ρ = 13.543 g/cm³
Mercury Manometer reading; h = 25.62 in
Acceleration due to gravity; g = 32.243 ft/s²
Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243
When we multiply and covert to psia gives; P_g = 12.562 psia
Thus;
P_abs = 14.666 + 12.562
P_abs = 27.228 psia
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Answer:
V = 56.8 mV
Explanation:
When a current I flows across a circuit element, if we assume that the dimensions of the circuit are much less than the wavelength of the power source creating this current, there exists a fixed relationship between the power dissipated in the circuit element, the current I and the voltage V across it, as follows:
P = V*I
By definition, power is the rate of change of energy, and current, the rate of change of the charge Q, so we can replace P and I, as follows:
E/t = V*q/t ⇒ E = V*Q
Solving for V:
V = E/Q = 94.2 mJ /1.66 C = 56.8 mV
