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vlabodo [156]
3 years ago
13

A concentric tube heat exchanger for cooling lubricating oil is comprised of a thin-walled inner tube of 25 mm diameter carrying

water and an outer tube of 45 mm diameter carrying the oil. The exchanger operates in counterflow with an overall heat transfer coefficient of 60W/m2K and the tabulated average properties given below. If the outlet temperature of the oil is 60oC, plot the temperature as a function of x and determine the total heat transfer, the outlet temperature of the water, and the required length.

Engineering
1 answer:
Triss [41]3 years ago
6 0

Find the attachment for complete solution

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A gasoline engine takes in air at 290 K, 90 kPa and then compresses it. The combustion adds 1000 kJ/kg to the air after which th
Inessa [10]

Answer:

attached below

Explanation:

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4 years ago
Which of the following types of protection is an employer required to pay for?
77julia77 [94]

Answer:

Hearing protection would be your answer!

Explanation:

This includes earplugs,muffs etc.

Hope it helps!

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4 years ago
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A system consists initially of nA moles of gas A at pressure p and temperature T and nB moles of gas B separate from gas A but a
Volgvan

Answer:

A) б = - R ( nA In Ya - nB In Yb )

B) s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced

Explanation:

A) assuming ideal gas behavior the expression for entropy produced

for a closed system : s2 - s1 = б

where : s1 ( initial entropy ) = nA sA ( T, P ) + nB sB ( T, P )

s2 ( final entropy ) = nA sA ( T, YaP ) + nB sB ( T, YbP )

∴ б = - R ( nA In Ya - nB In Yb )

B) Given that

Ya and Yb are less than 1  respectively, hence the value of б  = positive

also assuming the gases are identical

s2 = ( nA + nB ) s( T,P )

C) No entropy will be produced when same gas at same temperature and same pressure are mixed

5 0
3 years ago
Defective PPE must be
mel-nik [20]
I’m pretty sure it is given to your supervisor . If it isn’t then it’s inspected and repaired
6 0
3 years ago
How a single force is resolved along the perpendicular axis acting an angle theta with horizontal?​
Nataly [62]

Answer:

A single force, which is acting at angle θ from a horizontal axis, can be resolved into components which act along the perpendicular axis.

Consider the perpendicular axis x and y, where x represents the horizontal axis and y represents vertical axis.

The Force is resolved into 2 parts, one acts along x-axis and is represent by X. The other acts along y-axis and is represented by Y.

From the diagram we can see that the Force and its components X and Y makes up a right angles triangle, where θ is the angle from the x-axis

<h3 /><h3>Find X:</h3>

We know that:

cosθ = Base/Hypotenuse

cosθ = X/F

X = Fcosθ

<h3>Find Y:</h3>

We know that:

sinθ = Perpendicular/Hypotenuse

sinθ = Y/F

Y = Fsinθ

<h3>Relation of Force and its Components:</h3>

Force F can be represent by:

F = Fcosθ (along x-axis) + Fsinθ (along y-axis)

As they form a right angled triangle, we can use Pythagoras Theorem to show the relation between Force and its components.

Hypotenuse² = Base² + Perpendicular²

F² = X² + Y²

F² = (Fcosθ)² + (Fsinθ)²

F = \sqrt{(F\cos\theta)^2+(Fsin\theta)^2}

Where θ can be found by using any of the trignometric functions.

6 0
3 years ago
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