Answer:
The question is incomplete, below is the complete question
"The real power delivered by a source to two impedance, Z1=4+j5Ω and Z2=10Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."
answer:
a. 615W, 384.4W
b. 17.4A
Explanation:
To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.
recall that the symbol for admittance is Y and express as

Hence for each we have,

for the second impedance we have

we also determine the voltage cross the impedance,
P=V^2(Y1 +Y2)


The real power in the impedance is calculated as

for the second impedance

b. We determine the equivalent admittance

We convert the equivalent admittance back into the polar form

the source current flows is

Answer:
(B) FALSE
Explanation:
view factor
depends on the surface emissivity and the surface of geometry view factor is the term used in radiative heat transfer. View factor is depends upon the radiation which leave the surface and strike the surface.View factor is also called shape factor configuration factor it is denoted by 
Solution :
Given :
The power of the air‐conditioning (AC) unit is , W = 0.434 kW
The coefficient of performance or the COP of the air‐conditioning (AC) unit is given by = 6.22
Therefore he heat removed is given by , 

Now if the electricity is valued at 0.10 dollar per kW hour, then the operating cost of the air conditioning unit in 24 hours is given by = 0.10 x 2.7 x 24
= 6.48
Therefore the operating cost = $ 6.48 for 24 hours.
Answer:
Time taken by airplane to cover given distance = 2 hour
Explanation:
Given:
Distance cover by airplane = 1,000 miles
Velocity of airplane = 500 miles per hour
Find:
Time taken by airplane to cover given distance
Computation:
Time taken = Distance / Velocity(Speed)
Time taken by airplane to cover given distance = Distance cover by airplane / Velocity of airplane
Time taken by airplane to cover given distance = 1,000 / 500
Time taken by airplane to cover given distance = 2 hour