If the specific surface energy for magnesium oxide is 1.0 J/m2 and its modulus of elasticity is (225 GPa), compute the critical
stress required for the propagation of an internal crack of length 0.8 mm.
1 answer:
Answer:
critical stress required is 18.92 MPa
Explanation:
given data
specific surface energy = 1.0 J/m²
modulus of elasticity = 225 GPa
internal crack of length = 0.8 mm
solution
we get here one half length of internal crack that is
2a = 0.8 mm
so a = 0.4 mm = 0.4 × m
so we get here critical stress that is
...............1
put here value we get
=
= 18923493.9151 N/m²
= 18.92 MPa
You might be interested in
Answer:
a) , b)
Explanation:
a) The thermal efficiency is:
b) The coefficient of performance is:
Answer:
Depending on the amount of torque that is put in the motor, the new velocity is 550 rpm.
B.requires torque would decrease (I think)
Answer:
float
Explanation:
air has a density of 1.225 kg/m3 and that gas has only 1.2 but it depends if its kg/m3 or g/ml3