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igor_vitrenko [27]
3 years ago
9

Which of the following compound is most soluble in water a)glycerol b) ethyl alcohol c) ethylene glycol d)ethyl chloride

Chemistry
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

glycerol

Explanation:

it is thick sweet liquid.It is type of alcohol which has 3 OH groups

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Which statements correctly describe the decay rates of radioactive isotopes?
storchak [24]

Answer: b} The exact time when an individual atom will decay can be accurately predicted.

c} After each half-life, the amount of radioactive material is reduced by half.

Explanation:

All radioactive decay  follows first order kinetics.

Rate law expression for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process

a = initial amount of the reactant

a - x = amount left after decay process

Expression for calculating half life, which is the time taken by the half of the reactants to decompose is:

t_{1/2}=\frac{0.693}{k}


4 0
3 years ago
Read 2 more answers
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
Parents should avoid sharing their own mistakes with children. True/false
Vesna [10]
Parents SHOULDN'T avoid sharing their own mistakes with children.
6 0
3 years ago
Read 2 more answers
**ASAP**
jek_recluse [69]

the answer is C) . I hope this was helpful!

4 0
3 years ago
Read 2 more answers
A penny has a mass of 2.50g and the Moon has a mass of ×7.351022kg, How many moles of pennies have a mass equal to the mass of t
baherus [9]
Answer: 122 moles

Procedure:

1) Convert all the units to the same unit

2) mass of a penny = 2.50 g

3) mass of the Moon = 7.35 * 10^22 kg (I had to arrage your numbers because it was wrong).

=> 7.35 * 10^22 kg * 1000 g / kg = 7.35 * 10^ 25 g.

4) find how many times the mass of a penny is contained in the mass of the Moon.

You have to divide the mass of the Moon by the mass of a penny

7.35 * 10^ 25 g / 2.50 g = 2.94 * 10^25 pennies

That means that 2.94 * 10^ 25 pennies have the mass of the Moon, which you can check by mulitiplying the mass of one penny times the number ob pennies: 2.50 g * 2.94 * 10^25 = 7.35 * 10^25.

5) Convert the number of pennies into mole unit. That is using Avogadros's number: 6.022 * 10^ 23

7.35 * 10^ 25 penny * 1 mol / (6.022 * 10^ 23 penny) = 1.22* 10^ 2 mole = 122 mol.

Answer: 122 mol
8 0
3 years ago
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