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erik [133]
3 years ago
13

On a shelf sits a bottle of NaCl solutions with a molar concentration of 2.50 M and a total volume of 300 mL. If 15.0 mL of the

solution is added to 985 mL of pure water, what is the molar concentration of NaCl in the new solution
Chemistry
1 answer:
Stella [2.4K]3 years ago
8 0

Given :

On a shelf sits a bottle of NaCl solutions with a molar concentration of 2.50 M and a total volume of 300 mL. If 15.0 mL of the solution is added to 985 mL of pure water .

To Find :

The molar concentration of NaCl in the new solution.

Solution :

Molarity M is given by :

M=\dfrac{\text{Total number of moles}}{\text{Volume in liters}}

Now , 1000 ml of NaCl contains 2.5 moles of NaCl .

So , 15 ml of NaCl contains :

n=\dfrac{15\times 2.5}{1000}\\\\n=3.75\times 10^{-2}\ moles

New , volume V = 15 + 985 = 1000 ml = 1 L .

So , putting value of n and V in above equation :

M=\dfrac{3.75\times 10^{-2}}{1}\ M\\\\M=0.0375\ M

Therefore ,  the molar concentration of NaCl in the new solution is 0.0375 M .

Hence , this is the required solution .

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Ivanshal [37]

Explanation:

hydropower energy is:

-renewable

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3 0
3 years ago
A solution is made by adding 29.1 mL of concentrated perchloric acid ( 70.5 wt% , density 1.67 g/mL ) to some water in a volumet
Lera25 [3.4K]

Answer:

The concentration of the solution is 1.364 molar.

Explanation:

Volume of perchloric acid = 29.1 mL

Mass of the solution = m

Density of the solution = 1.67 g/mL

m=1.67 g/mL\times 29.1 mL=48.597 g

Percentage of perchloric acid in 48.597 solution :70.5 %

Mass of perchloric acid in 48.597 solution :

= \frac{70.5}{100}\times 48.597 = 34.261 g

Moles of perchloric acid = \frac{34.261 g}{100.46 g/mol}=0.3410 mol

In 29.1 mL of solution water is added and volume was changed to 250 mL.

So, volume of the final solution = 250 mL = 0.250 L (1 mL = 0.001 L)

Molarity=\frac{Moles}{Volume (L)}

=\frac{0.3410 mol}{0.250 L}=1.364 M

The concentration of the solution is 1.364 molar.

6 0
3 years ago
Chlorofluorocarbons (CFCs) are no longer used as refrigerants because they destroy the ozone layer. Trichlorofluoromethane (CCl₃
Daniel [21]

Answer:

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

Explanation:

Entropy :It is defined as amount of energy which is unable to do work or the measurement of randomness or disorderedness in a system.

S=\frac{Q}{T(Kelvins)}

Molar heat of molar vaporization of Trichlorofluoromethane = 24.8 kJ/mol

Temperature at which Trichlorofluoromethan boils , T= 296.95 K

The molar entropy of the evaporation of Trichlorofluoromethan :

=\frac{24.8 kJ/mol}{296.95 K}=0.083516 kJ/mol K = 83.516 J/molK

The molar entropy of the evaporation of Trichlorofluoromethan is 83.516 J/molK.

8 0
3 years ago
Which of kbr or ch3br is likely to have the higher normal boiling point?
allsm [11]

Answer:

KBr

Explanation

KBr is an ionic compound which have very high BP since they exist as 3D crystals

Methyl Bromide, CH3Br.  is a covalent compound which have low BP since they exist as individual molecules

8 0
3 years ago
How much energy is transferred from a plant to an herbivore that eats it? A. 5% B. 10% C. 20% D. 90%
Tema [17]

Answer:

B. 10%

Explanation:

6 0
3 years ago
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