Answer:
Percentage of Ba in the compound is 19.5%
Explanation:
Answer: 51.4 g of NaClO will be produced.
Explanation:
To calculate the moles :
According to stoichiometry :
1 moles of require = 2 moles of
Thus 0.69 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
As 1 mole of give = 1 mole of
Thus 0.69 moles of give = of
Mass of
Thus 51.4 g of NaClO will be produced
Answer:
J.J. Thomson
Explanation:
According to my book and wiki, Historically, the mass of the electron was determined directly from combining two measurements. The mass-to-charge ratio of the electron was first estimated by Arthur Schuster in 1890 by measuring the deflection of "cathode rays" due to a known magnetic field in a cathode ray tube. It was seven years later that J. J.
Please correct me if I'm wrong.
Answer:
okay I will help you just message me johnpatrick on messenger
To determine whether our equations are balanced, we must write the elements on the products side and also the reactants side. If the amount of the elements (coefficients and subscripts) are equal on both sides, we have a balanced equation.
Lets try (A)
2NaCl + H₂SO₄ → HCl + NaSO₄
Na=2 Na=1
Cl=2 Cl=1
H=2 H=1
Na=2 Na=1
S=1 S=1
O=4 O=4
Most of the elements here are not equal for both sides, therefore, A is not the answer.
Lets try (B)
2Na + S → 2NaS
Na=2 Na=2
S=1 S=2
This is a wrong answer because S is not equal on both sides. B is a wrong answer.
Lets try (C)
KOH + H2SO4 → KHSO4 + H2O
K=1 K=1
O= 1 O=1
H=1 H=1
H=2 H=2
S=1 S=1
O=4 O=4
THIS IS A BALANCED EQUATION!!!! ALL ELEMENTS ARE EQUAL ON BOTH SIDES!!!
Since we already know that C is our answer, we have no need to check D. Also, D is incorrect because N has 1 on reactants side, and 2 on the other. Therefore, we automatically know that D is wrong.
FINAL ANSWER: C IS OUR ANSWER, IT IS A BALANCED EQUATION. :)