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Vlada [557]
2 years ago
15

An ideal gas has a volume of 18.25 L at a temperature of 15.9 °C. The temperature of the gas is raised to 40.7 °C while the numb

er of moles and the pressure of the gas are kept constant. What is the new volume of the gas (in L)?
B: An ideal gas has a volume of 10.8 L at a temperature of 25.0 °C and a pressure of 60 atm. The pressure of the gas is reduced to 370.0 mmHg, but the temperature and number of moles of the gas are kept constant. What is the new volume of the gas (in L)?
Chemistry
2 answers:
Fynjy0 [20]2 years ago
8 0

Answer:

V₂ = V₁ / T₁ * T₂ . If you prefer to set the final volume and want to estimate the resulting temperature, then the equation of Charles' law changes to: T2=T1/T1 multiplied by v^2.

Rasek [7]2 years ago
6 0
Answer: Chapter 5 Supplemental Problem Answers

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3(x - 2) = 5(x + 4)<br><br>​
Tcecarenko [31]

Answer:

Uh first of all this is algebra but I'll answer this

First distribute the three and 5 (Multiply them by both terms inside parenthesis.

3x-6=5x+20

Then add like terms

8x=14

Divide 8 by 8 and 8 by 14

x = 14/8

Explanation:

5 0
3 years ago
Read 2 more answers
how much heat is absorbed when 15.0 g of liquid water is heated until the temperature increases by 16.0.
svlad2 [7]
N snsnnsnansnannnans
8 0
3 years ago
Calculate the energy(J) change associated with an electron transition from n=2 to n=5 in a Bohr hydrogen atom. Put answer in sci
Oliga [24]
The energy at n level of hydrogen atom energy level =13.6/n^2

substiture the respective n values in the equation above and find the difference in the energy levels

instagram : imrajsingh

gimme a follow^ :)
3 0
3 years ago
Read 2 more answers
Homes in rural areas where natural gas service is not available often rely on propane to fuel kitchen ranges. The propane is sto
Neporo4naja [7]

Answer:

2666.7 hours

Explanation:

The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption  of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.

PV = nRT ∴ n = PV/RT

n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane

Mass propane :

6.75 mol x 44 g/mol = 296.88 g

convert this to Kg:

296.88 g/ 1000 g/Kg = 0.30 Kg

calculate the volume in liters this represents by dividing by the density:

0.30 Kg / 0.5077 Kg/L =  0.59 L

changing this to gallons

0.59 L x  1 gallon/3.785 L = 0.15 gallon

and finally calculate how many hours the 400 gallons propane tank will deliver

400 gallon/ 0.15 gallon/hr = 2666.7 hr

6 0
3 years ago
Why is it important to test the crucible for cracks before heating it?
solmaris [256]

It important to test the crucible for cracks before heating it because it can break while performing the chemical reaction.

The crucible and the lid should be inspected to check for the before heating it to prevent the breaking while performing the reactions. if there are some breaks in the crucible then if we heat the crucible it can lead to breaking of the whole crucible and the material  from the crucible to come out and it will come in contact with the lid.

The crucible plays a important role while preforming the reactions, so. it important to check the cracks of the crucible before the heating of the crucible.

To learn more about crucible here

brainly.com/question/10237849

#SPJ4

7 0
1 year ago
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