Answer:
Percent yield of carbon monoxide is approximately 38%.
Explanation:
Given reaction : C + SiO₂ → Si + CO
On balancing it : 2C + SiO₂ → Si + 2CO
⇒ 2 mole of carbon produces 2 mole of carbon monoxide
or 2×12=24 g of carbon produces 2×(12+16)=56 g of carbon monoxide
⇒ Expected yield of carbon monoxide when 32.5g of carbon is heated with silicon dioxide is 32.5×
⇒ Expected yield = = 75.8 g
Actual yield is given as 28.8 g
⇒ The percent yield of carbon monoxide = ×100
= ×100
≅<u>38%</u>
5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.
Explanation:
The balanced equation:
2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)
data given:
volume of AgNO3 = 0.2 L
molarity of AgNO3 = 0.200 M
atomic weight of AgCl= 143.32 gram/mole
from the formula, number of moles can be calculated
Molarity =
number of moles of AgNO3 = 0.04
From the reaction:
2 moles of AgNO3 reacts to form 2 moles of AgCl
0.04 moles of AgNO3 reacts to form x mole of AgCl
=
= 0.04 moles of AgCl is formed
mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl
mass of AgCl = 0.04 x 143.32
= 5.732 grams of AgCl is formed.
