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Ket [755]
3 years ago
5

In a bowl of 50 skittles, you have 12 yellow, 9 orange, 11 red, and 13 green. The rest of the skittles are purple. What percenta

ge of the skittles are red? What percentage of the skittles are not green?
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answer:

percentage of red skittles = 22%

percentage of skittles that are not green = 74%

Explanation:

total skittles = 50

yellow = 12

orange = 9

red = 11

green = 13

purple = 50-12-9-11-13

= 5

1) percentage of red skittles

\frac{red \: skittles}{total \: skittles}  \times 100

\frac{11}{50}  \times 100

\frac{22}{10}

22\%

2) percentage of skittles that are not green

\frac{total \: skittles - green \: skittles}{total \: skittles} \times 100

\frac{50 -13 }{50}  \times 100

\frac{37}{50}  \times 100

74\%

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What is the percentage composition of ca in ca(po4)2​
Keith_Richards [23]

Explanation:

Element Symbol Mass Percent

Calcium Ca 38.763%

Oxygen O 41.265%

Phosphorus P 19.972%

5 0
3 years ago
A 1.2 L weather balloon on the
makkiz [27]

Answer:

330.95K

Explanation:

V₁ = 1.2L

T₁ = 25°C = (25 + 273.15)K = 298.15K

P₁ = 1.0 atm

P₂ = 0.74 atm

V₂ = 1.8L

T₂ =?

From combined gas equation,

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Solve for T₂

T₂ = (P₂ * V₂ * T₁) / (P₁ * V₁)

T₂ = (0.74 * 1.8 * 298.15) / (1.0 * 1.2)

T₂ = 397.1358 / 1.2

T₂ = 330.9465K

T₂ = 330.95K or T₂ = (330.95 - 273.15)°C = 57.8°C

8 0
3 years ago
Which is an example of a base?a(lemon juice b(baking soda c(an insolator d( water
bija089 [108]

Answer:

b) Baking soda

Explanation:

Baking soda is sodium hydrogen carbonate, NaHCO₃.

It reacts with water according to the equation

NaHCO₃ + H₂O ⇌ H₂CO₃ + NaOH

Thus, baking soda is a base because it increases the concentration of hydroxide ions in water.

<em>Water</em> is <em>neutral</em>.

<em>Lemon juice</em> is an <em>acid</em> because it contains citric acid.

An <em>insulator </em>is a substance that does not conduct electricity. Insulators are <em>neither acidic nor basic</em>.

3 0
3 years ago
Determine the ph of a 0. 35 m aqueous solution of CH3NH2 (methylamine). The kb of methylamine is?
guajiro [1.7K]

The pH of 0.35 M of CH₃NH₂ is 12.09 and the k_b for methylamine is 4.4 x 10⁻⁴.

<h3>What is pH?</h3>

pHis the quantitative measure of acidity and basicity of an aqueous or other liquid solution. The scale range goes from 0 to 14. Water has a pH of 7 and is neutral in nature.

<h3>What is dissociation constant?</h3>

The dissociation constant is an equilibrium constant that describes the dissociation or ionization of a base or an acid

k_a describes the dissociation of an acid

k_b describes the dissociation of a base

For methylamine,

CH_3NH_2 + H_2O\Leftrightarrow CH_3NH_3^+ + OH^-

Initial concentration of methylamine = 0.35 M

Initial concentration of products = 0

Let, at equilibrium concentration of CH₃NH₂ = 0.35 - x

Then, concentration of CH₃NH₃⁺ and OH⁻ is x and x respectively

k_b = \frac{[CH_3NH_3^+] [OH^-]}{[CH_3NH_2]}

The dissociation constant for methylamine, k_b = 4.4 x 10⁻⁴

4.4 \times 10^-^4 = \frac{x.x}{0.35} \\x^{2} = 4.4 \times 10^-^4 \times 0.35\\x^{2}  = 1.54  \times 10^-^4 \\

x =0.0124

pOH = -log[OH] = -log(0.0124) = 1.91

pH + pOH = 14

pH = 14 - 1.91 = 12.09

Thus, the pH of methylamine is 12.09 and k_b is 4.4 x 10⁻⁴

Learn more about pH:

brainly.com/question/172153

#SPJ4

7 0
2 years ago
A strong acid is one that:
HACTEHA [7]

Answer:

A strong acid completely ionizes in water.

5 0
3 years ago
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