If the change in entropy of the surroundings for a process at 451 k and constant pressure is -326 j/k, then heat flow absorbed (in kj) by the system is -147.026kJ.
<h3>What is entropy? </h3>
The entropy of particle is defined as how random it move. It shows the randomness of the system or may be disorders of the system. It is used to measure the unavailable energy for performing useful work.
Unit of entropy = J/K
<h3>Formula:</h3>
∆s = ∆Q/T
where,
∆s = change in entropy of the surrounding = -326J/K
∆Q = heat absorbed from surrounding
T = Temperature = 451K
∆Q = ∆s × T
∆Q = -326 × 451
∆Q = 147,026 J
∆Q = 147.026 kJ
Thus we find that the heat absorbed by the system is 147.026 kJ.
learn more about entropy:
brainly.com/question/14131507
#SPJ1
all of the above is the answer :)
Answer:
I would help but the picture will not load for me :(
Explanation:
Answer:
Explanation:
7) A block of wood
has a length of 10.2
cm, a width of 6 cm
and a height of 4.1
cm. The wood has
a total mass of 179
grams. What is the
volume of the
wood and what is
the density of the
wood?
volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3
DENSITY = M/V = 179gm/250.92 cm^3
=0.713 gm/cm^3
Answer:thermal energy
Explanation:Thermal radiation is the emission of electromagnetic rays from all matter that’s greater then zero
