A) See ray diagram in attachment (-6.0 cm)
By looking at the ray diagram, we see that the image is located approximately at a distance of 6-7 cm from the lens. This can be confirmed by using the lens equation:
where
q is the distance of the image from the lens
f = -10 cm is the focal length (negative for a diverging lens)
p = 15 cm is the distance of the object from the lens
Solving for q,
B) The image is upright
As we see from the ray diagram, the image is upright. This is also confirmed by the magnification equation:
where 
are the size of the image and of the object, respectively.
Since q < 0 and p > o, we have that 
, which means that the image is upright.
C) The image is virtual
As we see from the ray diagram, the image is on the same side of the object with respect to the lens: so, it is virtual.
This is also confirmed by the sign of q in the lens equation: since q < 0, it means that the image is virtual
Answer:
The question is incomplete, below is the complete question
"The displacement of a wave traveling in the negative y-direction is D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ), where y is in m and t is in s.
A) What is the frequency of this wave?
B) What is the wavelength of this wave?
C) What is the speed of this wave?"
Answers:
a. 
b. 
c. 
Explanation:
The equation of a wave is represented as
Where A=amplitude
w=angular frequency=2πf
K=wave numbers =2π/λ
since we re giving he equation D(y,t) = ( 4.60cm ) sin ( 6.20 y+ 60.0 t ),
we can compare and get the value for the wave number and angular frequency.
By comparing we have
w=60rads/s
k=6.20
a. to determine the frequency, from the expression fr angular wave frequency we have
w=2πf hence
f=w/2π
if we substitute we arrive at
b. to determine the wave length, we use
c. the wave speed v is express as the product of the frequency and the wavelength. Hence
The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
<h3>Conservation of energy</h3>
The amount of energy lost due to air resistance while she was bouncing is determined from the principle of conservation of energy.
ΔE = P.E - Ux
ΔE = mgh - ¹/₂kx²
ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²
ΔE = 3,360 J
Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
Learn more about energy here: brainly.com/question/13881533
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It would be a really bad idea to eat the snow because you obviously are trying to stay warm right? Well, the best thing to do is melt the snow. However, the process of melting the snow would have a few complications as well. But yes, the latter idea (drinking the snow) is a better idea (not the best).
