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Lesechka [4]
3 years ago
13

A train travels 2km in 100 seconds. find the velocity of the train

Physics
1 answer:
AVprozaik [17]3 years ago
3 0

Answer:

20m/s = 72km/h

Explanation:

change 2km=2000m

The speed of the train is

v.t=S <=> v=S/t=2000/100=20 m/s

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What is fission and how is it related to atomic energy
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Answer:

Fission is the release of atomic energy related to the splitting of nuclei.

M = M1 + M2 + E         where E = m c^2 energy from conversion of mass

if the daughter nuclei are less in total mass than the parent nucleus then the difference is released as atomic energy where E = m c^2 and m is the mass that has been lost in the conversion.

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Both deltas and mountains are
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3 years ago
Two large parallel conducting plates carrying opposite charges of equal magnitude are separated by 2.20 cm. If the surface charg
bekas [8.4K]

Answer:

5.3\times 10^3 N/C

Explanation:

We are given that

Distance between plates=d=2.2 cm=2.2\times 10^{-2} m

1 cm=10^{-2} m

\sigma=47nC/m^2=47\times 10^{-9}C/m^2

Using 1 nC=10^{-9} C

We have to find the magnitude of E in the region between the plates.

We know that the electric field for parallel plates

E=\frac{\sigma}{2\epsilon_0}

E_1=\frac{\sigma}{2\epsilon_0}

E_2=\frac{\sigma}{2\epsilon_0}

E=E_1+E_2

E=\frac{\sigma}{2\epsilon_0}+\frac{\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}C^2/Nm^2

Substitute the values

E=\frac{47\times 10^{-9}}{8.85\times 10^{-12}}

E=5.3\times 10^3 N/C

Hence, the magnitude of E in the region between the plates=5.3\times 10^3 N/C

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