We know, W = k. q₁q₂/ [1/r₁² - r₂² ]
Here, r₁ = R
r₂ = ∞
Substitute their values,
W = k. q₁q₂/ [1/R - 1/∞]
W = k. q₁q₂/ [1/R]
W = k. q₁q₂/ R
Hope this helps!
C. added an electron to the outer electron shell.
Explanation:
Atoms consist of three particles:
- Protons: they are located in the nucleus, they have positive charge of , and mass of
- Neutrons: they are also located in the nucleus, they have no electric charge, and mass similar to that of the proton
- Electrons: they orbit around the nucleus, they have negative charge of , and mass around 1800 smaller than the proton
Normally, atoms are neutral (no electric charge), because they have an equal number of protons and electrons.
However, sometimes atoms can give off or take electrons from other atoms. We have two cases:
- If an atom gives off an electron, it remains with an excess of positive charge, so it becomes a positive ion
- If an atom takes an electron from another atom, it remains with an excess of negative charge, so it becomes a negative ion
Therefore, in order to form a negative ion, the atom must have
C. added an electron to the outer electron shell
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The distance a speaker should be placed behind other sound to have an amplitude 1.50 times is 4.523 m.
<h3>What is wavelength?</h3>
The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.
Wavelength λ = v/f
Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.
λ = 343 m/s /1000 Hz
λ = 0.343 m
Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.
The amplitude of the waveform due to waves,
A = 2a cos (ΔΦ/2)
ΔΦ = 2π x Δx/λ
So, A = 2a cos (π x Δx/λ)
Substitute the values, we get
1.5a = 2a cos (3.14 x Δx/ 0.343)
Δx = 4.523 m
Thus, the distance is 4.523 m.
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Answer:
a basis or standard for evaluation, assessment, or comparison; a criterion.
Explanation:
Definition of reference point. : something that is used to judge or understand something else The professor used the study as a reference point for evaluating and discussing other theories.