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iogann1982 [59]
3 years ago
8

1. Two magnetic north poles will do which of the following?

Physics
1 answer:
RoseWind [281]3 years ago
8 0
Magnetic domains are which of the following?
You might be interested in
Hii:) anyone able to explain and help me with this question?
Assoli18 [71]

Answer:

No

Explanation:

The equation of state for ideal gases tells that:

pV=nRT

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature

In this problem, we have a fixed mass of gas. This means that the number of moles of the gas, n, does not change; also, the volume V remains the same, and R is a constant, this means that

p\propto T

So, as the pressure increases, the temperature increases.

However, here we want to understand what happens to the average distance between the molecules.

We have said previously that the number of moles n does not change: and therefore, the total number of molecules in has does not change either.

If we consider one dimension only, we can say that the average distance between the molecules is

d=\frac{L}{N}

where L is the length of the container and N the number of molecules. Since the volume of the container here does not change, L does not change, and since N is constant, this means that the average distance between the molecules remains the same.

4 0
3 years ago
A swing that is 9.2m long has a child in it who is swinging. what is its period in seconds
Fantom [35]
The child on a swing can be modeled as a simple pendulum.  The period of a simple pendulum is given by

T=2 \pi \sqrt{ \frac{L}{g} }=2 \pi \sqrt{ \frac{9.2m}{9.8 \frac{m}{s^2} } }=6.09s
8 0
3 years ago
The speed limit on some interstate highways is roughly 80 km/h. What is this in meters per second? How many miles per hour is th
sergey [27]

Answer:

1) Speed in m/s equals 22.22 m/s.

2) Speed in miles per hour equals 49.712 mph.

Explanation:

Since we know that in 1 kilometer there are 1000 meters and in 1 hour there are 3600 seconds hence we can write

80km/h=\frac{80\times 1000m}{3600s}=22.22m/s

Now we know that 1 mile equals 1.609 kilometer  hence we conclude that 1 kilometer equals \frac{1}{1.609}=0.6214mile

Hence

80km/h=\frac{80\times 0.6214miles}{1h}=49.712mph

3 0
4 years ago
The mass of an object is 60kg on the surface of the earth what will be its weight on the surface of the moon
iris [78.8K]

Answer:

Wm = 97.2 [N]

Explanation:

We must make it clear that mass and weight are two different terms, the mass is always preserved that is to say this will never vary regardless of the location of the object. While weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

m = mass = 60 [kg]

g = gravity acceleration = 10 [m/s²]

But in order to calculate the weight of the body on the moon, we must know the gravitational acceleration of the moon. Performing a search of this value on the internet, we find that the moon's gravity is.

gm = 1.62 [m/s²]

Wm = 60*1.62

Wm = 97.2 [N]

8 0
3 years ago
A 2000-kg truck is being used to lift a 400-kg boulder B that is on a 50-kg pallet A. Knowing the acceleration of the rear-wheel
anzhelika [568]

Answer:

(a) reaction at each front wheel is 5272N (upward)

(b) force between boulder and pallet is 4124N (compression)

Explanation:

Acceleration of the truck a_{t = 1 m/s^{2}  (to the left)

when the truck moves 1 m to the left, the boulder is B and pallet A are raised 0.5 m, then,

a_{A} =  0.5 m/s^{2} (upward) , a_{B} =  0.5 m/s^{2} (upward)

Let T be tension in the cable

pallet and boulder: ∑fy = ∑(fy)eff = 2T- (m_{A} + m_{B})g =  (m_{A} + m_{B})a_{B}

                                  = 2T- (400 + 50)*(9.81 m/s^{2}) = (400 + 50)*(0.5 m/s^{2})

                        T = 2320N

Truck:  M_{R} = ∑(M_{R})eff: = -N_{f} (3.4m) + m_{T} (2.0m) - T (0.6m)= m_{T} a_{T} (1.0m)

Nf = (2.0m)(2000 kg)(9.81 m/s^{2} )/3.4m -  (0.6 m)(2320 N)/3.4m + (1.0 m)(2000 kg)(1.0 m/s^{2})  = 11541.2N - 409.4N - 588.2N = 10544N

∑fy (upward) = ∑(fy)eff: N_{f} + N_{R} - m_{T}g = 0

                                       10544 + N_{R}  - (2000kg)(9.81 m/s^{2} ) = 0

                N_{R} = 9076N

   ∑fx (to the left) = ∑(fx)eff:  F_{R} - T = m_{T} a_{T}

                                      F_{R} = 2320N + (2000kg)(9.81 m/s^{2} ) = 4320N

(a) reaction at each front wheel:

1/2 N_{f} (upward): 1/2 (10544N) = 5272N (upward)

(b) force between boulder and pallet:

∑fy (upward) = ∑(fy)eff: N_{B} + M_{B}g - m_{B}a_{B}

            N_{B} = (400kg)(9.81 m/s^{2}) + (400kg)(0.5 m/s^{2}) = 4124N (compression)

3 0
4 years ago
Read 2 more answers
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