when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens
1 answer:
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Answer:
Explanation:
The equation for centripetal force is
. We have all the values we need except for the radius. We have the circumference of the circle, though, so we will solve for the radius using that and the fact that C = 2πr:
3.04 = 2(3.1415)r and
r = .484 m, to the correct number of sig fig's.
Now that we have everything we need and isolating the v NOT squared:
and filling in:
. This answer will need 2 sig fig's since 2100 has 2 sig fig's in it. That means that the velocity of the test car is
1.1 m/sec
Answer:
a. The object can have zero acceleration and, simultaneously, nonzero velocity.
c. The object can have nonzero velocity and nonzero acceleration simultaneously.
d. The object can have zero velocity and, simultaneously, nonzero acceleration.
Explanation:
For an object in simple harmonic motion, the total mechanical energy (sum of elastic potential energy and kinetic energy) is constant:
(1)
where
k is the spring constant
x is the displacement
m is the mass
v is the speed
We can also notice that the force on the spring is given by Hook's law:
And since according to Newton's law we have F = ma, this can be rewritten as
which means that the acceleration is proportional to the displacement.
So by looking again at eq.(1), we can now states that:
- when the displacement is zero, x=0, the acceleration is zero, a=0, and the velocity is maximum
- when the velocity is zero, v=0, the acceleration is maximum, which occurs when the displacement is maximum
- in all the other intermediate situations, both velocity and acceleration are non-zero
So the correct answers are
a. The object can have zero acceleration and, simultaneously, nonzero velocity.
c. The object can have nonzero velocity and nonzero acceleration simultaneously.
d. The object can have zero velocity and, simultaneously, nonzero acceleration.