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Naddika [18.5K]
4 years ago
10

A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At

tains a final velocity of 445 meters/second after 4.50 seconds.
Physics
1 answer:
Pani-rosa [81]4 years ago
8 0

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

s=vt-\frac{1}{2}at^2

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

a=99.0 m/s^2 is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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The halter add the distance to the jump in meters is 0.55 m.

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When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

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Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

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Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

ΔR = ΔVx' x t

ΔR = 1.34 x 0.41

ΔR =0.55m

Thus, the halter add the distance to the jump in meters is 0.55 m.

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3 0
2 years ago
1. A change in an object's speed has a(n) _________ effect on its kinetic energy than a change in its mass.
vredina [299]
A change in an object's speed has a(n) _________ effect on its kinetic energy than a change in its mass = <span>A greater effect.</span>
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3 years ago
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A radar used to detect the presence of aircraft receives a pulse that has reflected off an object 5 ✕ 10−5 s after it was transm
Sunny_sXe [5.5K]

Answer:

7500 m

Explanation:

The radar emits an electromagnetic wave that travels towards the object and then it is reflected back to the radar.

We can call L the distance between the radar and the object; this means that the electromagnetic wave travels twice this distance, so

d = 2L

In a time of

t=5\cdot 10^{-5}s

Electromagnetic waves travel in a vacuum at the speed of light, which is equal to

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Since the electromagnetic wave travels with constant speed, we can use the equation for uniform motion ,so:

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A 14 kg block lifted 5 m has a gravitational potential energy of
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Answer:

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Explanation:

potential energy = m × h × g

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hence, gravitational potential energy of the object is 700J

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