A rocket initially at rest accelerates at a rate of 99.0 meters/second ^2.Calculate the distance covered by the rocket if it. At

Question

4 years ago

10

tains a final velocity of 445 meters/second after 4.50 seconds.

1 answer:

Pani-rosa [81] · Answer 1 · 2022-01-02T06:18:14+03:00

The distance covered is 1000 m

Explanation:

The rocket is moving by uniformly accelerated motion, so we can find the distance it covers by using the following suvat equation:

$s=vt-\frac{1}{2}at^2$

where

s is the distance covered

v is the final velocity

t is the time

a is the acceleration

For the rocket in this problem, we have:

v = 445 m/s is the final velocity

$a=99.0 m/s^2$ is the acceleration

t = 4.50 s is the time

Substituting, we find the distance covered:

$s=(445)(4.50)-\frac{1}{2}(99.0)(4.50)^2=1000 m$

Learn more about accelerated motion:

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