A 100-gram sample of material requires 1220 calories of heat energy to raise its temperature from 20 0C to 80 0C. What is the sp
1 answer:
Taking into account the definition of calorimetry, sensible heat and latent heat, the specific heat capacity of the material is 0.203 .
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).
The amount of heat a body receives or transmits is determined by:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
<h3>Specific heat capacity of the material</h3>In this case, you know:
- Q= 1220 calories
- c= ?
- m= 100 g
- ΔT=Tfinal - Tinitial= 80 C - 20 C= 60 C
Replacing in the definition of amount of heat:
1220 calories= c× 100 g× 60 C
Solving:
c= 1220 calories÷ (100 g× 60 C)
<u><em>c= 0.203 </em></u>
Finally, the specific heat capacity of the material is 0.203 .
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