Question

A 100-gram sample of material requires 1220 calories of heat energy to raise its temperature from 20 0C to 80 0C. What is the specific heat capacity of the material?

Answer 1

Taking into account the definition of calorimetry, sensible heat and latent heat, the specific heat capacity of the material is 0.203 $\frac{calories}{gC}$.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

Specific heat capacity of the material

In this case, you know:

• Q= 1220 calories
• c= ?
• m= 100 g
• ΔT=Tfinal - Tinitial= 80 C - 20 C= 60 C

Replacing in the definition of amount of heat:

1220 calories= c× 100 g× 60 C

Solving:

c= 1220 calories÷ (100 g× 60 C)

c= 0.203 $\frac{calories}{gC}$

Finally, the specific heat capacity of the material is 0.203 $\frac{calories}{gC}$.

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